Question

我已经阅读并尝试了很多关于stackoverflow的例子，然后才询问，但到目前为止还没有运气。我想要做的是解析一个json数组，我从php / mysql回来用于在Android中使用。我的代码可以解决这个问题，我可以将json转换为转换后的字符串：

[{"username":"lawn edge","distance":"0.00766418723166294"},{"username":"bbq","distance":"0.00876051437108357"},{"username":"Tablet","distance":"0.0140815866739065"}]

我试图只提取＆＃34;用户名＆＃34;并将它们发送到textview。我尝试过的大多数示例只是生成一个空文本视图，或者它在上面看时会转储整个json字符串。我最接近的是使用以下代码：

private void returnJson() {
    // TODO Auto-generated method stub

    try {

        httpPostproximity = new HttpPost(
                "http://vtolblog.com/finddistance.php");
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(3);

        nameValuePairs.add(new BasicNameValuePair("lat", lat));
        nameValuePairs.add(new BasicNameValuePair("lng", lng));
        nameValuePairs.add(new BasicNameValuePair("username", check));
        httpPostproximity
                .setEntity(new UrlEncodedFormEntity(nameValuePairs));

        HttpResponse response = httpclient.execute(httpPostproximity);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();

    } catch (Exception e) {
        playerlist.setText("error3");
    }

    try {

        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\r\n");
        }
        is.close();
        result = sb.toString();
        result.trim();
    } catch (Exception e) {
        playerlist.setText("error2");
    }
    try {
        JSONObject json_data = new JSONObject(result);
        JSONArray jArreglo = new JSONArray(result);
        for (int i = 0; i < jArreglo.length(); i++) {
            json_data = jArreglo.getJSONObject(i);
            Log.i("log_tag", "Player: " + json_data.getString("username"));
            // Get an output to the screen
            jsonplayers += "\n\t" + jArreglo.getJSONObject(i);
        }

    } catch (JSONException e) {
        Log.e("log_tag", "Error parsing data " + e.toString());
        playerlist.setText("Error parsing json");
    }

    playerlist.setText(jsonplayers);

    return;

    // end of returnJson()
}

如果我改变了playerlist.setText（结果）;它将显示上面引用的json数组，所以我假设代码在那之前是可以的吗？我离开了吗？如果您还需要其他任何帮助，请提前告知我并提前致谢！

Answer 1

我认为你在网上获得例外：

JSONObject json_data = new JSONObject(result);

因为结果是JSONArray而不是JSONObject，请尝试评论此行。

Android json解析没有产生预期的结果

1 个答案: