这是我的php代码实现插入db:
<?php
require_once "includes/db_data_inc.php";
try
{
$DBH = new PDO("mysql:host=$db_host;dbname=$db_name",$db_user,$db_pass);
$DBH->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$cathy = new patient($_POST['name'],
$_POST['surname'],
$_POST['address'],
$_POST['birth-place'],
$_POST['province'],
$_POST['dt'],
$_POST['gender'],
$_POST['select']);
$STH = $DBH->prepare("INSERT INTO users (name,
surname,
address,
birth_place,
province,
dt,
sex,
case) value (:name
:surname,
:address,
:birth_place,
:province,
:dt,
:sex,
:case)");
$STH->execute((array)$cathy);
}
catch (PDOException $pdoe)
{
error_log($pdoe->getMessage());
die("An error was encountered!");
}
?>
这里是db_data_inc.php
,其中存储了db_info以及我创建对象患者的位置
$db_host = 'localhost';
$db_name = 'main_db';
$db_user = 'root';
$db_pass = 'root';
/* Create an object patient */
class patient
{
public $name;
public $surname;
public $address;
public $birth_place;
public $province;
public $birth_date;
public $sex;
public $case;
function __construct($nm,$sur,$addr,$bp,$pr,$bd,$sx,$cs)
{
$this->name = $nm;
$this->surname = $sur;
$this->address = $addr;
$this->birth_place = $bp;
$this->province = $pr;
$this->birth_date = $bd;
$this->sex = $sx;
$this->case = $cs;
}
}
我收到此错误:
[10-Feb-2012 21:14:29] SQLSTATE[HY093]: Invalid parameter number: parameter was not defined
但我没有意识到原因......为什么我收到这个错误?有人可以帮帮我吗?错误在哪里?
答案 0 :(得分:1)
不确定这是否是导致错误的原因,但在插入语句中,CASE是一个MySQL保留字,应该使用反引号进行转义。
$STH = $DBH->prepare("INSERT INTO users (name,
surname,
address,
birth_place,
province,
dt,
sex,
`case`) value (:name
:surname,
:address,
:birth_place,
:province,
:dt,
:sex,
:case)");
答案 1 :(得分:1)
在您的查询中,您使用:dt
作为占位符,但在类构造函数中使用$this->birth_date
。
一旦投射,这将创建一个索引为“birth_date'
的数组,该数组与命名参数"dt"
不匹配:选择其中一个。