我编写了以下方法将Hex String转换为int:
-(long)intFromHexString:(NSString*) string
{
char tempChar;
int temp;
tempChar=[string characterAtIndex:[string length]-1];
temp=strtol(&tempChar, NULL, 16);
NSLog(@"***>%c = %i",tempChar,temp);
return temp;
}
大部分时间它都能正常工作,但有时会遇到这样的大问题:
2012-02-10 01:09:28.516 GameView[7664:f803] ***>7 = 7
2012-02-10 01:09:28.517 GameView[7664:f803] ***>7 = 7
2012-02-10 01:09:28.518 GameView[7664:f803] ***>D = 13
2012-02-10 01:09:28.519 GameView[7664:f803] ***>5 = 5
2012-02-10 01:09:28.520 GameView[7664:f803] ***>5 = 5
2012-02-10 01:09:28.520 GameView[7664:f803] ***>D = 13
2012-02-10 01:09:28.521 GameView[7664:f803] ***>4 = 4
2012-02-10 01:09:28.522 GameView[7664:f803] ***>4 = 4
2012-02-10 01:09:28.522 GameView[7664:f803] ***>5 = 5
2012-02-10 01:09:28.523 GameView[7664:f803] ***>4 = 1033 <------this
2012-02-10 01:09:28.524 GameView[7664:f803] ***>C = 12
2012-02-10 01:09:28.524 GameView[7664:f803] ***>B = 11
2012-02-10 01:09:28.525 GameView[7664:f803] ***>3 = 3
2012-02-10 01:09:28.526 GameView[7664:f803] ***>3 = 48 <------this
2012-02-10 01:09:28.527 GameView[7664:f803] ***>B = 11
有谁能告诉我我的代码有什么问题?
答案 0 :(得分:5)
您正在将指向单个字符的指针传递给strtol()
,而不是以NUL结尾的字符串,因此strtol()
有时会超出您给出的字符。 (例如,“1033”是它找到“409”的结果,而不仅仅是“4”。)
修正:
-(long)intFromHexString:(NSString*) string
{
char tempChar[2];
int temp;
tempChar[0]=[string characterAtIndex:[string length]-1];
tempChar[1] = 0;
temp=strtol(tempChar, NULL, 16);
NSLog(@"***>%c = %i",tempChar[0],temp);
return temp;
}