Question

我试图获取std::string值并将其用作std::getline()函数中的分隔符但没有我做什么编译器给我错误。这就是我想要做的事情：

std::stringstream ss(s);
    std::string item;
    std::string delim ="&&=";
    int ssize = delim.size();
    int newssize = ssize+1;
    char del[SSIZE];  // also here when i try gives error
    strcpy(del,delim.c_str());

        char * delrr[1024] = delim.c_str();  //gives error 

        while(std::getline(ss,item,delrr)) {
           elems.push_back(item);
    }

错误即时获取总是关于const char * convertion。

 error C2440: 'initializing' : cannot convert from 'const char *' to 'char *[1024]'
1>        There are no conversions to array types, although there are conversions to references or pointers to arrays
1>.\UT.cpp(179) : error C2780: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided
1>        d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(527) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2784: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::stringstream'
1>        d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2784: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::stringstream'
1>        d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2782: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : template parameter '_Elem' is ambiguous
1>        d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1>        could be 'char **'
1>        or       'char'

更新：
找到了答案： How do I tokenize a string in C++?
http://www.codeproject.com/Articles/23198/C-String-Toolkit-StrTk-Tokenizer

Answer 1

getline（）的第三个参数是char，而不是char数组。见this。如果您需要多个分隔符或由多个字符组成的分隔符，则无法使用此功能。

Answer 2

std :: string :: c_str（）为您提供指向字符数组的指针。为了使用c_str()调用的结果填充字符数组，您需要使用strcpy()或strncpy()，因为这些实际上会复制C样式字符串。

此外，您已将delrr声明为1024个字符指针而非1024个字符的数组，这是真的意图吗？

转换str字符串以在std :: getline分隔符中使用

2 个答案: