Question

我在用户进入特定位置时设置了通知。当用户在通知栏输入半径电话节目通知并一次又一次地振动时会发生什么。即使我清除通知电话保持震动请帮助我！这是通知代码：

import android.app.Dialog;
import android.app.Notification;
import android.app.NotificationManager;
import android.app.PendingIntent;
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.graphics.Color;
import android.location.LocationManager;
import android.os.Bundle;
import android.util.Log;
import android.view.Window;
import android.view.WindowManager;
import android.widget.TextView;


    public class ProximityIntentReceiver extends BroadcastReceiver {

    private static int NOTIFICATION_ID = 0;
    public static final String EVENT_ID_INTENT_EXTRA = "EventIDIntentExtraKey";
    public static final String PLACE_NAME = "PLACE";
    public static final String ITEM_NAME = "ITEM";
    String Place_Name = "",Item_Name = "";


    @Override
    public void onReceive(Context context, Intent intent) {
         Log.v("entered","" );
        String key = LocationManager.KEY_PROXIMITY_ENTERING;
        //Bundle extras = getIntent().getExtras(); 
        NOTIFICATION_ID = intent.getIntExtra(EVENT_ID_INTENT_EXTRA, -1);
        Place_Name = intent.getStringExtra(PLACE_NAME);
        Item_Name =  intent.getStringExtra(ITEM_NAME);
        Boolean entering = intent.getBooleanExtra(key, false);
         Log.v(Place_Name,Item_Name );

        if (entering) {
            Log.d(getClass().getSimpleName(), "entering");
        }
        else {
            Log.d(getClass().getSimpleName(), "exiting");
        }


        NotificationManager notificationManager = 
            (NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE);

        PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, null, 0);       

        Notification notification = createNotification();
        notification.setLatestEventInfo(context, "Hello You are near to this", Place_Name + "  and your task is  " + Item_Name, pendingIntent);

        notificationManager.notify(NOTIFICATION_ID, notification);

    }

    private Notification createNotification() {
        Notification notification = new Notification();

        notification.icon = R.drawable.newnotification;
        notification.when = System.currentTimeMillis();

        notification.flags |= Notification.FLAG_AUTO_CANCEL;
        notification.flags |= Notification.FLAG_SHOW_LIGHTS;

        notification.defaults |= Notification.DEFAULT_VIBRATE;
        notification.defaults |= Notification.DEFAULT_LIGHTS;

        notification.ledARGB = Color.WHITE;
        notification.ledOnMS = 1500;
        notification.ledOffMS = 1500;

        return notification;
    }
}

我做错了什么？

Answer 1

试试这个：

notification.defaults |= Notification.DEFAULT_LIGHTS;
notification.defaults |= Notification.FLAG_ONLY_ALERT_ONCE;
notification.defaults |= Notification.DEFAULT_SOUND;
notification.flags |= Notification.FLAG_AUTO_CANCEL;
notification.defaults |= Notification.DEFAULT_VIBRATE;

Answer 2

notification.when用于告诉系统何时发出通知。

在真实设备上振动一次，然后在android中通知（近似警报）

2 个答案: