Question

即使我使用INSERT INTO而不是EXISTS，是否可以获取id？如何修改它，这将带给我插入记录的ID或已存在的记录的ID？如果可能的话！

INSERT INTO Timeline (name, ts)
SELECT @name, @ts
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name=@name AND ts = @ts);

我有一个名为“ id ”的列，其中包含自动增量整数我怎么能得到ID的价值？

欢呼声

Answer 1

您保证(name,ts)是唯一的，所以这应该可以解决问题。

INSERT INTO Timeline (name, ts)
SELECT @name, @ts
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name=@name AND ts = @ts);

SELECT id, name, ts from TimeLine
WHERE name=@name AND ts = @ts

Answer 2

你可以使用输出子句：

insert into Timeline output inserted.name 
SELECT @name, @ts
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name=@name AND ts = @ts);

您也可以在更新中执行此操作

update Timeline 
set name = @name
output deleted.name as OLD_NAME, inserted.name as NEW_NAME

编辑：

运行这个，你会理解：

create table Timeline(
id int not null primary key identity(1,1),
name varchar(50),
ts varchar(50))

insert into timeline output inserted.ID
values ('first record', 'ts') 
--it will show 1


insert into Timeline output inserted.ID 
SELECT 'first record', 'ts'
union select 'new record', 'ts'
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name='first record' AND ts = 'ts')
--ir will show 2 because the 1 already exits

sqlite INSERT INTO ...哪里没有EXISTS并获得id？

2 个答案: