Question

我正在尝试为其中一张发票选择所有佣金数据，该发票将向最高销售人员支付佣金。（可以为每张发票支付多个佣金。）我只有CommissionReport表，其中包含每张发票的每个销售人员的佣金。

invoice_number     salesperson_id    commission_amt
----------------   ----------------  ----------------
            1001   Bob                          30.00
            1002   Alison                       64.50
            1002   Charlie                     110.25

这段代码工作正常，但我的潜意识是尖叫，我不需要嵌套三个深度的子选择。有人可以帮我理顺吗？

select

    invoice_number,
    salespeson_id,
    commission_amt  

from

    CommissionReport CR

    join

    (   select    top 1 invoice_number
        from      CommissionReport CR2
        group by  CR2.invoice_number
        having    count(*) = 

        (   select    max(CR3.cnt)
            from      

            (   select    invoice_number,
                          cnt = count(*)
                from      CommissionReport CR4
                group by  invoice_number
            ) CR3

        )

    ) CR2 on CR2.invoice_number = CR.invoice_number

非常感谢。

斯科特

Answer 1

我不明白这些要求，这是我在Mssql中的第一个查询...但检查一下是否有效：

select cr.invoice_number, cr.salesperson_id, cr.commission_amt  
from CommissionReport CR
where cr.invoice_number in (
    select top 1 invoice_number
    from CommissionReport CR2
    group by CR2.invoice_number
    order by count(*) desc
)

简化包含聚合的嵌套子选择

1 个答案: