我想获得与一个像素具有相同颜色的所有像素坐标
List<cv::Point> GetAllPixels(cv::Point x)
{
//imp
}
如何在EmguCV或OpenCV中执行此操作?
答案 0 :(得分:5)
以下是使用OpenCV C ++的可能解决方案:
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <iostream>
#include <vector>
using namespace std;
using namespace cv;
std::vector<cv::Point> getPixelsWithColor(const cv::Mat& src, cv::Scalar targetColor)
{
assert(src.type() == CV_8UC3);
std::vector<cv::Point> identicalPoints;
for(int row = 0; row < src.rows; ++row)
{
for(int col = 0; col < src.cols; ++col)
{
cv::Vec3b currPixel = src.at<cv::Vec3b>(row, col);
if(currPixel[0] == targetColor.val[0] &&
currPixel[1] == targetColor.val[1] &&
currPixel[2] == targetColor.val[2])
{
identicalPoints.push_back(cv::Point(col, row));
}
}
}
return identicalPoints;
}
int main(int argc, char** argv)
{
Mat squares = imread("colored_squares.png");
const Scalar RED = Scalar(0, 0, 255); // OpenCV is BGR order...
vector<Point> redPixelLocations;
redPixelLocations = getPixelsWithColor(squares, RED);
Mat redMask = Mat::zeros(squares.size(), CV_8UC1);
vector<Point>::iterator i;
for(i = redPixelLocations.begin(); i != redPixelLocations.end(); ++i)
{
redMask.at<uchar>(*i) = 255;
}
imshow("Squares", squares);
imshow("Red mask", redMask);
waitKey();
return 0;
}
我使用了这个输入图像:
并实现了这个输出图像:
享受! :)
答案 1 :(得分:0)
答案应该让你开始。另请考虑使用Cmp
函数
对于IplImage
,它可能是这样的:
IplImage *img, *col_img, *mask_img;
// initialise images appropriately...
svSet(col_img, [colour of your choise]);
cvCmp(img, col_img, mask_img, CV_CMP_EQ);
使用mask_img
提取坐标。您可以找到cv::Mat
的等效操作。