用java导入kml

时间:2012-02-08 19:26:03

标签: java kml jak

我正在尝试使用jak导入mkl文件,但是我收到以下错误:

javax.xml.bind.UnmarshalException:意外元素(uri:“http://earth.google.com/kml/2.2”,local:“kml”)。预期的要素是 ... 然后是一个大清单

有没有其他人遇到这个问题?

这是代码:

final Kml kml = Kml.unmarshal(new File("../data/Eemskanaal.kml"));
        final Placemark placemark = (Placemark) kml.getFeature();
        Point point = (Point) placemark.getGeometry();
        List<Coordinate> coordinates = point.getCoordinates();
        for (Coordinate coordinate : coordinates) {
            System.out.println(coordinate.getLatitude());
            System.out.println(coordinate.getLongitude());
            System.out.println(coordinate.getAltitude());
        }

这是kml文件:

<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://earth.google.com/kml/2.2">
<Document>
  <name>BU00100107 Verspreide huizen Eemskanaal (ten zuiden)</name>
  <description><![CDATA[description]]></description>
  <Placemark>
    <name>BLA!</name>
    <description><![CDATA[]]></description>
    <styleUrl>#style1</styleUrl>
    <Polygon>
      <outerBoundaryIs>
        <LinearRing>
          <tessellate>1</tessellate>
          <coordinates>
            6.941796,53.314914,0.000000
            6.942705,53.310923,0.000000
            6.952713,53.305394,0.000000
            6.954853,53.300262,0.000000
            6.954239,53.296317,0.000000
            6.962271,53.295483,0.000000
            6.995900,53.287338,0.000000
            6.995013,53.285264,0.000000
            6.996842,53.281429,0.000000
            6.991748,53.278255,0.000000
            6.990729,53.275234,0.000000
            6.988361,53.274477,0.000000
            6.990120,53.271780,0.000000
            6.984540,53.272709,0.000000
            6.984543,53.274393,0.000000
            6.980317,53.274404,0.000000
            6.975829,53.272503,0.000000
            6.974816,53.271125,0.000000
            6.963342,53.271937,0.000000
            6.955082,53.265909,0.000000
            6.945183,53.269634,0.000000
            6.940684,53.273351,0.000000
            6.935942,53.273875,0.000000
            6.934392,53.276351,0.000000
            6.929104,53.272181,0.000000
            6.909544,53.265952,0.000000
            6.908803,53.269015,0.000000
            6.909151,53.278897,0.000000
            6.888166,53.279161,0.000000
            6.887788,53.279639,0.000000
            6.886750,53.280950,0.000000
            6.886729,53.280977,0.000000
            6.888260,53.281856,0.000000
            6.895912,53.286254,0.000000
            6.892976,53.288089,0.000000
            6.891571,53.290803,0.000000
            6.887323,53.298046,0.000000
            6.887729,53.309725,0.000000
            6.887583,53.309816,0.000000
            6.888683,53.311891,0.000000
            6.893966,53.313119,0.000000
            6.924732,53.311548,0.000000
            6.929655,53.312392,0.000000
            6.934810,53.315353,0.000000
            6.941796,53.314914,0.000000
          </coordinates>
        </LinearRing>
      </outerBoundaryIs>
    </Polygon>
    <Polygon>
      <outerBoundaryIs>
        <LinearRing>
          <tessellate>1</tessellate>
          <coordinates>
            6.905549,53.283453,0.000000
            6.908790,53.282516,0.000000
            6.912146,53.283305,0.000000
            6.916480,53.287575,0.000000
            6.916764,53.288072,0.000000
            6.915251,53.288369,0.000000
            6.915097,53.290097,0.000000
            6.912526,53.292361,0.000000
            6.908052,53.290971,0.000000
            6.905569,53.288875,0.000000
            6.905549,53.283453,0.000000
          </coordinates>
        </LinearRing>
      </outerBoundaryIs>
    </Polygon>
</Placemark>
</Document>
</kml>

欢迎任何其他解决方案

3 个答案:

答案 0 :(得分:2)

这是我快速而又肮脏的方式:)

public static Kml getKml(InputStream is) throws Exception {
    String str = IOUtils.toString( is );
    IOUtils.closeQuietly( is );
    str = StringUtils.replace( str, "xmlns=\"http://earth.google.com/kml/2.2\"", "xmlns=\"http://www.opengis.net/kml/2.2\" xmlns:gx=\"http://www.google.com/kml/ext/2.2\"" );
    ByteArrayInputStream bais = new ByteArrayInputStream( str.getBytes( "UTF-8" ) );
    return Kml.unmarshal(bais);
}

答案 1 :(得分:1)

我对Jak不熟悉,但如果您使用OGC Schema,则名称空间不同。

http://earth.google.com/kml/2.2

OGC名称空间是

http://www.opengis.net/kml/2.2

Google extension schema使用

http://www.google.com/kml/ext/2.2

也是。在将KML作为开放标准提供给OGC之前,Google使用了您正在使用的命名空间。

答案 2 :(得分:0)

命名空间不正确,但如果您有1700个文件并且这是唯一的问题,您可以考虑简单地使用Kml.unmarshal的双参数形式(文件文件,布尔验证)。

final Kml kml = loadXMLFile("../data/Eemskanaal.kml");
private static Kml loadXMLFile(String path) {
        Kml kml = null;
        try {
            kml = Kml.unmarshal(path);
        } catch (RuntimeException ex) {
            kml = Kml.unmarshal(new File(path), false);
        }
        return kml;
    }

我还使用了以下cheezy perl脚本来更正我的文件。

$ cat ~/bin/fixxmlns
#!/usr/bin/perl

for (@ARGV) {

    open (FH,"<$_");
    open (NFH,">$_.x");

    $look = 1;
    while ($r = <FH>) {
        if ($look && $r =~ /earth.google.com/) {
            $r = qq{<kml xmlns="http://www.opengis.net/kml/2.2" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:gx="http://www.google.com/kml/ext/2.2">\n};
            $look = 0;
            }
        print NFH $r;
    }
    close (NFH);
    close (FH);
    rename("$_", "$_.orig");
    rename("$_.x", "$_");
}
$ fixxmlns *.kml
$ find parentdir -name "*.kml" -print0 | xargs -0 fixxmlns