Question

Python Web服务代码：

import web 
from soaplib.wsgi_soap import SimpleWSGISoapApp
from soaplib.service import soapmethod
from soaplib.serializers import primitive as soap_types

urls = ("/hello", "HelloService",
        "/hello.wsdl", "HelloService",
        )
render = web.template.Template("$def with (var)\n$:var")



class SoapService(SimpleWSGISoapApp):
    """Class for webservice """
    @soapmethod(soap_types.String,_returns=soap_types.String)
    def hello(self,message):
        """ Method for webservice"""
        return "Hello world "+message



class HelloService(SoapService):
    """Class for web.py """
    def start_response(self,status, headers):
        web.ctx.status = status
        for header, value in headers:
            web.header(header, value)


    def GET(self):
        response = super(SimpleWSGISoapApp, self).__call__(web.ctx.environ, self.start_response)
        return render("\n".join(response))


    def POST(self):
        response = super(SimpleWSGISoapApp, self).__call__(web.ctx.environ, self.start_response)
        return render("\n".join(response))

app=web.application(urls, globals())

if __name__ == "__main__":
    app.run()

PHP代码：

<?php

    @ini_set("soap.wsdl_cache_enabled", "0");


    $client = new SoapClient('http://localhost:8080/hello.wsdl');

    echo("<pre>");
    var_dump($client->__getFunctions());
    echo("</pre>");
    $params = array('World');


    try {
        print_r($client->__soapCall('hello', $params));

    } catch (SoapFault $exception) {
        echo $exception;
    }
?>

当我运行我的php代码时，它会报告下面的信息

SoapFault异常：[helloFault] hello（）只需要2个参数（1 给出）在C：\ website \ cosmetics \ src \ test02.php：15堆栈跟踪：＃0 C：\网站\化妆品\ SRC \ test02.php（15）： SoapClient-＆gt; __ soapCall（'hello'，数组）＃1 {main}

如何解决这个问题？感谢。

Answer 1

不确定SoapClient究竟是什么，但它看起来只需要另一个参数。文件说了什么？

使用PHP调用Python Web服务

1 个答案: