NSMutableArray和NSArray初始化

时间:2012-02-08 08:12:16

标签: objective-c nsmutablearray nsarray

是否有更好的方法来初始化objective-c中的二维数组:

NSNumber *a = [[NSNumber alloc] initWithInt:0];
NSNumber *b = [[NSNumber alloc] initWithInt:1];
NSMutableArray *template = [[NSMutableArray alloc] initWithCapacity:16];
switch (myInt) {
    case 0:
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, a, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, a, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, a, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, a, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        [template addObject:[[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil]];
        break;
/* more */
}

3 个答案:

答案 0 :(得分:0)

我无法在阵列中找到规律性。至少你可以将一些代码包装成循环

id obj = [[NSArray alloc] initWithObjects:b, b, b, b, b, b, b, b, nil];

for (int i = 0; i<9; ++i){
    [template addObject: obj];
}

答案 1 :(得分:0)

假设你想制作一个NSNumber的二维数组

const int templateContent[][8] = { // put your data to this array
    1, 1, 1, 1, 1, 1, 1, 1,
    1, 0, 1, 1, 1, 1, 1, 1,
    // more...
};
const int dim = sizeof(templateContent)/sizeof(int[8]);
NSNumber *numbers[2]; // assume your only need two numbers
for (int i = 0; i < sizeof(numbers)/sizeof(id); i++) {
    numbers[i] = [NSNumber numberWithInt:i];
}
NSMutableArray *template = [[NSMutableArray alloc] initWithCapacity:16];
for (int i = 0; i < dim; i++) {
    [template addObject:[NSArray arrayWithObjects:
                         numbers[templateContent[i][0]], 
                         numbers[templateContent[i][1]], 
                         numbers[templateContent[i][2]], 
                         numbers[templateContent[i][3]], 
                         numbers[templateContent[i][4]], 
                         numbers[templateContent[i][5]], 
                         numbers[templateContent[i][6]], 
                         numbers[templateContent[i][7]], nil]];
}

答案 2 :(得分:0)

使用nsdictionary来保存数字,然后将字典存储在nsarray