Question

我正在编写一个针对潜在客户联系表单的脚本，需要将前10个潜在客户发送到电子邮件1，第二个10表示发送电子邮件2，依此类推，直到收到电子邮件4，然后又回到电子邮件1.

这是我为登陆页面制作的旋转器，但它每次旋转1次而不是等待10次，然后旋转。我如何修改它以满足我的需求？

此外，显然每次'刷新'都不会发生这种情况。需要一个单独的代码组，它将放在表单的action =“whatever.php”中，这就是增加它的代码。

<?php

//these are the email addresses to be rotated
$email_address[1] = 'email1@email.com';
$email_address[2] = 'email2@email.com';
$email_address[3] = 'email3@email.com';
$email_address[4] = 'email4@email.com';

//this is the text file, which will be stored in the same directory as this file, 
//count.txt needs to be CHMOD to 777, full privileges, to read and write to it.
$myFile = "count.txt";

//open the txt file
$fh = @fopen($myFile, 'r');
$email_number = @fread($fh, 5);
@fclose($fh);

//see which landing page is next in line to be shown.
if ($email_number >= count($email_address)) {
    $email_number = 1;
} else {
    $email_number = $email_number + 1;
}

//write to the txt file.
$fh = fopen($myFile, 'w') or die("can't open file");
$stringData = $email_number . "\n";
fwrite($fh, $stringData);
fclose($fh);

//include the landing page
echo $email_address[$email_number]; 

//terminate script
die();

?>

Answer 1

我从你的问题中理解的是，会有提交线索的表格，当提交线索时，它必须遵循你的逻辑。如果我错了，请纠正我。

如果是这样的话，使用两个像track.txt这样的文本文件。该文本文件的初始内容为1,0。这意味着潜在客户将被发送到第一个电子邮件ID 0次。

因此，在表单的动作脚本中包含以下代码。

<?php
$email_address[1] = 'email1@email.com';
$email_address[2] = 'email2@email.com';
$email_address[3] = 'email3@email.com';
$email_address[4] = 'email4@email.com';

$myFile = "track.txt";

//open the txt file
$fh = @fopen($myFile, 'r');
$track = @fread($fh, 5);
@fclose($fh);

$track = explode(",",$track);
$email = $track[0];
$count = $track[1];

if($count >= 10)
{
  $count=0;
  if($email >= count($email_address))
  {
    $email = 1;
  }
  else
  {
    $email++;
  }
} 
else
{
  $count++;
}

$track = $email.",".$count;

//write to the txt file.
$fh = fopen($myFile, 'w') or die("can't open file");
fwrite($fh, $track);
fclose($fh);

//send lead to $email

＆GT;

如何构建PHP旋转器

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