Question

使用Socket.IO的WebSocket我已经成功管理了我的家用电脑上的聊天应用程序，其中index.html和app.js（服务器）位于一起。由于我的webhost不提供WebSockets，我想在我的计算机上托管app.js（服务器）以及它在我的webhost上连接的实际网页。我在建立连接时遇到困难。我的端口已转发。我相信我的app.js中的一些内容，我需要更改以建立链接。这是我的代码

app.js（服务器，运行本地计算机）

var app = require('express').createServer()
var io = require('socket.io').listen(app);

app.listen(8080);

// routing
app.get('/', function (req, res) {
  res.sendfile('http://mywebhost.com/chat.php');
});

// usernames which are currently connected to the chat
var usernames = {};

// rooms which are currently available in chat
var rooms = ['room1','room2','room3'];

io.sockets.on('connection', function (socket) {

// when the client emits 'adduser', this listens and executes
socket.on('adduser', function(username){
    // store the username in the socket session for this client
    socket.username = username;
    // store the room name in the socket session for this client
    socket.room = 'room1';
    // add the client's username to the global list
    usernames[username] = username;
    // send client to room 1
    socket.join('room1');
    // echo to client they've connected
    socket.emit('updatechat', 'SERVER', 'you have connected to room1');
    // echo to room 1 that a person has connected to their room
    socket.broadcast.to('room1').emit('updatechat', 'SERVER', username + ' has connected to this room');
    socket.emit('updaterooms', rooms, 'room1');
});

// when the client emits 'sendchat', this listens and executes
socket.on('sendchat', function (data) {
    // we tell the client to execute 'updatechat' with 2 parameters
    io.sockets.in(socket.room).emit('updatechat', socket.username, data);
});

socket.on('switchRoom', function(newroom){
    // leave the current room (stored in session)
    socket.leave(socket.room);
    // join new room, received as function parameter
    socket.join(newroom);
    socket.emit('updatechat', 'SERVER', 'you have connected to '+ newroom);
    // sent message to OLD room
    socket.broadcast.to(socket.room).emit('updatechat', 'SERVER', socket.username+' has left this room');
    // update socket session room title
    socket.room = newroom;
    socket.broadcast.to(newroom).emit('updatechat', 'SERVER', socket.username+' has joined this room');
    socket.emit('updaterooms', rooms, newroom);
});

// when the user disconnects.. perform this
socket.on('disconnect', function(){
    // remove the username from global usernames list
    delete usernames[socket.username];
    // update list of users in chat, client-side
    io.sockets.emit('updateusers', usernames);
    // echo globally that this client has left
    socket.broadcast.emit('updatechat', 'SERVER', socket.username + ' has disconnected');
    socket.leave(socket.room);
});
});

chat.php（在webhost上运行）

<script>
var socket = io.connect(\'http://scope.bnetweb.org:8080\');
// various irrelevant javascript

app.js中的

我很确定我需要更改

app.get('/', function (req, res) {
  res.sendfile('http://mywebhost.com/chat.php');
});

还有其他什么？或者完全删除它？我认为这是Socket.IO确保没有未经授权的连接的方式。在实现这一目标时，我们非常感谢您的帮助。

Answer 1

解决方法就是不要将它们分开。 IT似乎很多都有这个问题，他们不能在不同的主机上混合使用服务器和客户端。可能Socket.IO很快就会变得容易。如果有其他人想出更好的选择，请回复。

Socket.IO WebSocket服务器/页面不同的主机

1 个答案: