我有一个项目,对其他Jars有一些依赖。我目前使用JavaDoc插件和Assembly插件生成我的项目的.zip,其中包含我的Jar,依赖项Jars和javadoc。
但是,我想把事情搞砸,以便.zip中只有一个Jar,以及相关的JavaDoc。我知道程序集插件+ jar-with-dependencies是我的朋友,但我如何解决这个问题,以便我可以打包一个包含这个jar的.zip以及我的JavaDoc?
我的pom的相关部分如下:
<properties>
<assemblyJar>${project.build.finalName}.jar</assemblyJar>
<assemblyJwd>${project.build.finalName}-jar-with-dependencies.jar</assemblyJwd>
<java.code.version>1.4</java.code.version>
</properties>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2.1</version> <!-- 2.3 might be needed -->
<configuration>
<descriptors>
<descriptor>src/assembly/dist-jwd.xml</descriptor>
</descriptors>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
</configuration>
<executions>
<execution>
<id>make-jwd</id>
<phase>prepare-package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>2.2.1</version> <!-- 2.3 might be needed -->
<configuration>
<descriptors>
<descriptor>src/assembly/dist.xml</descriptor>
</descriptors>
</configuration>
<executions>
<execution>
<id>make-zip</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
dist-jwd.xml的相关部分:
<id>dist-jwd</id>
<includeBaseDirectory>true</includeBaseDirectory>
<files>
<file>
<fileMode>444</fileMode>
<source>target/${assemblyJar}</source>
<outputDirectory></outputDirectory>
</file>
</files>
<dependencySets>
<dependencySet>
<outputDirectory>lib</outputDirectory>
<scope>compile</scope>
<excludes>
<exclude>javax.servlet:servlet-api</exclude>
</excludes>
<useProjectArtifact>false</useProjectArtifact>
</dependencySet>
</dependencySets>
dist.xml的相关部分:
<id>dist-zip</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>true</includeBaseDirectory>
<fileSets>
<fileSet>
<fileMode>444</fileMode>
<directory>target/site/apidocs</directory>
<outputDirectory>javadoc</outputDirectory>
</fileSet>
</fileSets>
<files>
<file>
<fileMode>444</fileMode>
<source>target/${assemblyJwd}</source>
<outputDirectory></outputDirectory>
</file>
</files>
目前我收到错误:
[ERROR] Failed to execute goal org.apache.maven.plugins:maven-assembly-plugin:2.2.1:single (make-jwd) on project deviceinsight-api-java: Failed to create assembly: Error adding file to archive: /Users/barmistead/Mercurial/deviceinsight-print/target/deviceinsight-api-java-3.1.16-1-SNAPSHOT-jar-with-dependencies.jar isn't a file. -> [Help 1]
我猜这是一个可能的鸡蛋问题,所以如果maven没有优雅的解决方案,那么我将不得不手动做一些事情。但是,我认为我想要做的事情非常普遍,所以我认为会有一个简单的方法。
答案 0 :(得分:0)
我最终放弃并在maven之后运行.sh脚本来做我想做的事。
Unix救援!