获得md5校验和的完成百分比

时间:2012-02-07 18:37:07

标签: python cryptography md5

我目前正在获得md5校验和,如下所示:

>>> import hashlib
>>> f = open(file)
>>> m = hashlib.md5()
>>> m.update(f.read())
>>> checksum = m.hedxigest()

我需要返回大型视频文件的校验和,这需要几分钟才能生成。如何实现百分比计数器,以便在运行时打印每个百分比的完成百分比。类似的东西:

>>> checksum = m.hedxigest()
1% done...
2% done...
etc.

3 个答案:

答案 0 :(得分:8)

您可以反复调用update()方法并将文件以块的形式提供给它。因此,您可以自己显示进度。

import hashlib
import os

def digest_with_progress(filename, chunk_size):
    read_size = 0
    last_percent_done = 0
    digest = hashlib.md5()
    total_size = os.path.getsize(filename)

    data = True
    f = open(filename)
    while data:
        # Read and update digest.
        data = f.read(chunk_size)
        read_size += len(data)
        digest.update(data)

        # Calculate progress.
        percent_done = 100 * read_size / total_size
        if percent_done > last_percent_done:
            print '%d%% done' % percent_done
            last_percent_done = percent_done
    f.close()
    return digest.hexdigest()

当我尝试print digest_with_progress('/bin/bash', 1024)时,这就是我得到的:

1% done
2% done
3% done
4% done
5% done
6% done
7% done
8% done
9% done
10% done
11% done
12% done
13% done
14% done
15% done
16% done
17% done
18% done
19% done
20% done
21% done
22% done
23% done
24% done
25% done
26% done
27% done
28% done
29% done
30% done
31% done
32% done
33% done
34% done
35% done
36% done
37% done
38% done
39% done
40% done
41% done
42% done
43% done
44% done
45% done
46% done
47% done
48% done
49% done
50% done
51% done
52% done
53% done
54% done
55% done
56% done
57% done
58% done
59% done
60% done
61% done
62% done
63% done
64% done
65% done
66% done
67% done
68% done
69% done
70% done
71% done
72% done
73% done
74% done
75% done
76% done
77% done
78% done
79% done
80% done
81% done
82% done
83% done
84% done
85% done
86% done
87% done
88% done
89% done
90% done
91% done
92% done
93% done
94% done
95% done
96% done
97% done
98% done
99% done
100% done
b114ecaab65bc5b02f5a129bd29d1864

以下是此文件的实际详细信息。

$ ls -l /bin/bash; md5sum /bin/bash
-rwxr-xr-x 1 root root 971384 Nov 30 16:31 /bin/bash
b114ecaab65bc5b02f5a129bd29d1864  /bin/bash

请注意,如果chunk_size太大,则无法获得预期的输出。例如,如果我们为/bin/bash读取100 KB块而不是1 KB块,这就是您所看到的。

10% done
21% done
31% done
42% done
52% done
63% done
73% done
84% done
94% done
100% done
b114ecaab65bc5b02f5a129bd29d1864

这种方法的局限性在于我们只有在读取了摘要后才计算进度。因此,如果块大小太大,每次读取块并更新摘要时,进度中的百分比差异将超过1%。更大的块大小可以更快地完成工作。因此,您可能希望放宽每个百分比的打印百分比完成条件,以提高效率。

答案 1 :(得分:4)

您应该使用f.read(N_BYTES)以块的形式阅读文件,跟踪文件的距离,并将块传递给m.update。这是昂贵的操作,而不是md5.hexdigest

答案 2 :(得分:4)

嗯,这不是hedxigest()调用需要一段时间,而是文件的读取。

考虑到这一点,用一个循环替换m.update(f.read()),逐个块地读取文件,更新校验和,并定期打印进度报告。