内联表达式评估

Question

有没有办法可以为循环内联？

already_inserted = True
for i in indexes:
    already_inserted = already_inserted and bitfield[i]

Answer 1

already_inserted = all(bitfield[i] for i in indexes)

Answer 2

怎么样：

already_inserted = all(bitfield[i] for i in indexes)

Answer 3

all（）函数接受iterable并自动遍历所有元素并将bool应用于每个元素。因此，写下来就足够了：

already_inserted = all(bitfield)