Question

我想在我的网站上创建一个“所有内容”页面，这将是我的所有用户活动。所以我需要从两个表“images”和“user_favorites”制作sql并输出所有这个html设计

我的桌子结构：

用户

id

图片

id
user_id
image
description
date

user_favorites

id
date

我有 sql 查询

function users_everything($user_id)
{
    $sql = "SELECT 
                i.description as text, 
                UNIX_TIMESTAMP(i.date) as image_date, 
                COALESCE ( imgcount.cnt, 0 ) as comments,
                fav.id as favorite_id,
                r.image as favorited_image,
                u2.username as favorite_user,
                t.image as favorite_user_image                                                            
            FROM users u
            LEFT JOIN images i ON i.user_id = u.id
            LEFT JOIN images p ON p.id = (SELECT b.id FROM images AS b where u.id = b.user_id ORDER BY b.id DESC LIMIT 1)
            LEFT JOIN (SELECT image_id, COUNT(*) as cnt FROM commentaries GROUP BY image_id  ) imgcount ON i.id = imgcount.image_id

            LEFT JOIN user_favorites fav ON fav.user_id = u.id                
            LEFT JOIN images r ON r.id = fav.image_id
            LEFT JOIN users u2 ON u2.id = r.user_id                                
            LEFT JOIN images t ON t.id = (SELECT b.id FROM images AS b where u2.id = b.user_id ORDER BY b.id DESC LIMIT 1)                                                                

            WHERE i.user_id = ?
            ";

    $query = $this->db->query($sql, $user_id);

    return $query->result_array();
}

我的“图片”表有1条记录和“user_follow”2条记录，但是如果我做了foreach它返回两个收藏夹并且两个图像（图像）被复制。

我不会像之前的所有页面那样将不同页面的数据呈现给不同的html结构。我想你有经验并帮助我

Answer 1

您需要将平面记录数组转换为树结构，其中每个图像都包含收藏夹列表。类似的东西：

$images = array();
foreach($everything_list as $item)
{
    // Check to see if already encountered this image
    $imageId = $item['image_id'];
    if (!isset($images[$imageId]))
    {
        // New image
        $image = array();

        // Do this for each image attribute
        $image['image_id'] = $item['image_id'];

        $image['favorites'] = array();
        $images[$imageId] = $image;
    }
    // Add Favorite
    $favorite = array();

    // Do this for each favorite attribute
    $favorite['favorite_id'] = $item['favorite_id'];

    $images[$imageId]['favorites'][] = $favorite;
}
print_r($images);

使所有页面表示来自不同html结构中的不同表的数据

1 个答案: