目前使用核心数据。我有一个表,我试图在这些行中检索信息:
SELECT item, COUNT(*) FROM myTable GROUP BY item;
为了产生这种结果:
+---------+------+-------+
| item | COUNT(*) |
+---------+------+-------+
| group 1 | 2 |
| group 2 | 5 |
| group 3 | 8 |
+---------+------+-------+
我有一个明智的想法是使用 NSExpression ,希望核心数据为我完成所有工作。我开始转动轮子。 count:表达式函数正在崩溃。例外不是很清楚。使用其他表达式函数(例如 sum:)不会使应用程序崩溃。
将结果存储在 NSFetchedResultsController 中会很不错。我已经探索了其他选择,其中没有一个不太吸引人。编写SQL查询并将其解决更有意义,而不是在这种情况下使用Core Data作为SQL包装器吗?
您的参考源代码如下。
NSExpression *keyPathExpression = [NSExpression expressionForKeyPath:@"item"];
NSExpression *totalExpression = [NSExpression expressionForFunction:@"count:" arguments:[NSArray arrayWithObject:keyPathExpression]];
NSExpressionDescription * totalExpressionDescription = [[NSExpressionDescription alloc] init];
[totalExpressionDescription setExpression:totalExpression];
[totalExpressionDescription setExpressionResultType:NSInteger64AttributeType];
[totalExpressionDescription setName:@"totalInstances"];
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:@"myEntity" inManagedObjectContext:self.managedObjectContext];
NSArray *propertiesToFetch = [[NSArray alloc] initWithObjects:strFieldName, totalExpressionDescription, nil];
[fetchRequest setEntity:entity];
[fetchRequest setReturnsDistinctResults:YES];
[fetchRequest setResultType:NSDictionaryResultType];
[fetchRequest setPropertiesToFetch:propertiesToFetch];
[fetchRequest setFetchBatchSize:20];
NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:strFieldName ascending:YES];
NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil];
[fetchRequest setSortDescriptors:sortDescriptors];
NSFetchedResultsController* aFetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:[self managedObjectContext] sectionNameKeyPath:nil cacheName:nil];
...
NSError *error = nil;
if (![self.fetchedResultsController performFetch:&error])
{
NSLog(@"Unresolved error %@, %@", error, [error userInfo]);
abort();
}
答案 0 :(得分:14)
这可以像你最初提出的那样使用NSExpression,在我的设计示例中,我有一个名为“Person”的实体,其中包含一个名为“emailAddress”的属性,我希望得到它的计数。
NSPropertyDescription *propDesc = [[[[model entitiesByName] objectForKey:@"Person"] propertiesByName] objectForKey:@"emailAddress"];
NSExpression *emailExpr = [NSExpression expressionForKeyPath:@"emailAddress"];
NSExpression *countExpr = [NSExpression expressionForFunction:@"count:" arguments:[NSArray arrayWithObject:emailExpr]];
NSExpressionDescription *exprDesc = [[NSExpressionDescription alloc] init];
[exprDesc setExpression:countExpr];
[exprDesc setExpressionResultType:NSInteger64AttributeType];
[exprDesc setName:@"count"];
NSFetchRequest *fr = [NSFetchRequest fetchRequestWithEntityName:@"Person"];
[fr setPropertiesToGroupBy:[NSArray arrayWithObject:propDesc]];
[fr setPropertiesToFetch:[NSArray arrayWithObjects:propDesc, exprDesc, nil]];
[fr setResultType:NSDictionaryResultType];
NSArray *results = [moc executeFetchRequest:fr error:&error];
我写了一段代码,用1000条记录预先填充数据库:
NSArray *emailAddresses = [NSArray arrayWithObjects:@"test@test.com", @"1@1.com", @"1@2.com", @"roam@test.com", @"foo@foo.com", nil];
for (int i = 0; i < 1000; i++) {
NSManagedObject *person = [NSEntityDescription insertNewObjectForEntityForName:@"Person" inManagedObjectContext:moc];
[person setValue:[NSNumber numberWithInt:i] forKey:@"aNumber"];
[person setValue:[[NSUUID UUID] UUIDString] forKey:@"aUUID"];
[person setValue:[emailAddresses objectAtIndex:(i % [emailAddresses count])] forKey:@"emailAddress"];
}
以上代码将每个电子邮件地址插入200次,结果如下:
2012-05-31 15:17:42.160 Scratch[16084:10d03] CoreData: sql: SELECT t0.ZEMAILADDRESS, COUNT( t0.ZEMAILADDRESS) FROM ZPERSON t0 GROUP BY t0.ZEMAILADDRESS
2012-05-31 15:17:42.162 Scratch[16084:10d03] CoreData: annotation: sql connection fetch time: 0.0024s
2012-05-31 15:17:42.163 Scratch[16084:10d03] CoreData: annotation: total fetch execution time: 0.0029s for 5 rows.
(gdb) po results
(NSArray *) $2 = 0x0f811280 <_PFArray 0xf811280>(
{
count = 200;
emailAddress = "1@1.com";
},
{
count = 200;
emailAddress = "1@2.com";
},
{
count = 200;
emailAddress = "foo@foo.com";
},
{
count = 200;
emailAddress = "roam@test.com";
},
{
count = 200;
emailAddress = "test@test.com";
}
)
答案 1 :(得分:0)