Question

我在Android应用程序开发方面相当新，我试图从SQLite数据库中获取行以显示为Listactivity，但这不起作用，程序意外终止。这是代码：

package ankur.test.app;

import android.app.ListActivity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class testMenu extends ListActivity{

    HotOrNot Infor = new HotOrNot(this);
    {
        Infor.open();
    }
    String[] result = Infor.getList();
    {
        Infor.close();
    }


    @Override
    protected void onCreate(Bundle ankurtestlist) {
        // TODO Auto-generated method stub
        super.onCreate(ankurtestlist);
        setListAdapter(new ArrayAdapter<String>(testMenu.this, android.R.layout.simple_list_item_2, result));

    }

    @Override
    protected void onListItemClick(ListView l, View v, int position, long id) {
        // TODO Auto-generated method stub
        super.onListItemClick(l, v, position, id);
        Object cheese = result[position];
    /*  try{
        Class ourClass = Class.forName("ankur.test.app."+ cheese);
        Intent ourIntent = new Intent(testMenu.this, ourClass);
        startActivity(ourIntent);
        }catch(ClassNotFoundException e){
            e.printStackTrace();
        }*/
    }
}

这是另一个类中的方法：

public String[] getList() {
        // TODO Auto-generated method stub
        String[] columns = new String[]{ KEY_ROWID, KEY_NAME, KEY_HOTNESS};
        Cursor c = ourDatabase.query(DATABASE_TABLE, columns, null, null, null, null, null);
        ArrayList name = new ArrayList(); 
        int i = 0;

        int iName = c.getColumnIndex(KEY_NAME);

        for (c.moveToFirst(); !c.isAfterLast(); c.moveToNext()){
            name.add(c.getString(iName));
            i++;
        }

        String[] result = (String[]) name.toArray();
        return result;
    }

任何帮助都将不胜感激。

Answer 1

似乎您遇到了上下文问题，只需将新Infor = HotOrNot(this);初始化为onCreate()并编辑代码，

String[] result;
HotOrNot Infor;

@Override
    protected void onCreate(Bundle ankurtestlist) {
        super.onCreate(ankurtestlist);\

        Infor = new HotOrNot(this);
        Infor.open();
        result = Infor.getList();
        Infor.close();
        setListAdapter(new ArrayAdapter<String>(testMenu.this, android.R.layout.simple_list_item_2, result));
    }

使用SQLite数据库填充列表

1 个答案: