Question

我的问题似乎很容易，但我真的无法解决它。在某些时候，我的代码会在ImageView内的LinearLayout内显示一堆图片（AlertDialog）。问题是不是所有东西都显示出来。

这是我的代码：

public  LinearLayout createLayout(String text) {
    LinearLayout ll = new LinearLayout(this.c);

    int res;
    for(int i=0; i<text.length(); ++i) {
        res = this.c.getResources().getIdentifier("pigpen_" + Character.toLowerCase(text.charAt(i)), "drawable", this.c.getPackageName());
        ImageView iv = new ImageView(this.c);
        iv.setPadding(5, 0, 0, 5);
        iv.setImageResource(res);
        ll.addView(iv);
    }
    return ll;
}

DialogAlert的代码：

protected ResultDialog(final Context context, CharSequence title, LinearLayout ll) {
    super(context);

    ll.setPadding(10, 5, 10, 5);

    this.setView(ll);
    this.setTitle(title);
}

正如您所看到的，结果并不好。你知道为什么吗？

Answer 1

问题是您的LinearLayout没有任何尺寸。宽度和高度都是0.所以一切都很完美。

你没有打电话给setLayoutParams，这就是全部。

ll.setLayoutParams(new LinearLayout.LayoutParams(FILL_PARENT, FILL_PARENT));

Answer 2

您可以使用HorizontalScrollView包装LinearLayout。这样你可以添加很多图像并滚动查看它们。

Answer 3

    LinearLayout ll = new LinearLayout(this.c); 
    ArrayList<Integer> alImages = new ArrayList<Integer>();
    ll.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT));

    for(int i=0; i<text.length(); ++i) {
        cur = text.charAt(i);
        pos = this.getCharAlphabetPosition(cur);
        if(pos > 0 && pos < alphabetId.length) {
            res = alphabetId[pos];
            alImages.add(res);
        }
    }
    gv.setAdapter(new ImageAdapter(this.c, alImages));
    gv.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));

    gv.setNumColumns(GridView.AUTO_FIT);
    gv.setColumnWidth(25);

    ll.addView(gv);
}

Et ma classe ImageAdapter： public class ImageAdapter扩展BaseAdapter实现ListAdapter { 私有语境c; private ArrayList alImages;

public ImageAdapter(Context c, ArrayList<Integer> alImages) {
    this.c = c;
    this.alImages = alImages;
}

public int getCount() {
    return this.alImages.size();
}

public Integer getItem(int position) {
    return this.alImages.get(position);
}

public long getItemId(int position) {
    return 0;
}

public View getView(int position, View convertView, ViewGroup parent) {
    ImageView imageView;
    if (convertView == null) {  // if it's not recycled, initialize some attributes
        imageView = new ImageView(this.c);
        imageView.setLayoutParams(new GridView.LayoutParams(25, 25));
        imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
        imageView.setPadding(5, 0, 0, 5);
    } else {
        imageView = (ImageView) convertView;
    }

    imageView.setImageResource(this.getItem(position));
    return imageView;
}

}

LinearLayout不会显示所有内容

3 个答案: