Question

我有一个每页显示10行的表。现在，给定一个项目的ID，我如何获得该项目所在的“页面”？

换句话说，我正在寻找给定记录ID的偏移量（10的倍数）。

SELECT * FROM items
WHERE category = "category"
LIMIT ?, 10      <----- TRYING TO FIGURE OUT HOW TO GET ? OFFSET GIVEN ID
ORDER BY id DESC

Answer 1

这应该这样做;

SELECT 10*FLOOR(COUNT(id)/10) FROM items where id < YOUR_ID

Answer 2

试试这个：

SET @rownum = 0; 
Select sub.*, 10 * Floor(sub.rownum / 10) as pagenum
from
(
   Select *,  (@rownum:=@rownum+1) as rownum
   from items order by id desc
) sub
where sub.ID = givenID;

MySQL获得偏移，给定限制，排序依据和位置ID

2 个答案: