我想比较数组[0]到数组末尾的距离,并用键显示最短距离。
阵 ( [0] =>排列 ( [city] =>排列 ( [0] =>瑞德特 [1] =>居尔皮普 )
[distance] => 14.4
)
[1] => Array
(
[city] => Array
(
[0] => Array
(
[0] => Reduit
[1] => Ebe
)
[1] => Bees Village
[2] => Phoen Trunk Rd
[3] => Riv,Phoenix
[4] => St l Rd
[5] => Geoes Guibert St
[6] => Curepipe
)
[distance] => 1.4
)
[2] => Array
(
[city] => Array
(
[0] => Array
(
[0] => Reduit
[1] => Riv,Phoenix
)
[1] => St l Rd
[2] => Geoes Guibert St
[3] => Curepipe
)
[distance] => 3.4
)
[3] => Array
(
[city] => Array
(
[0] => Array
(
[0] => Reduit
[1] => Ebene
)
[1] => Belles Village
[2] => Phoenix Trunk Rd
[3] => Riverside,Phoenix
[4] => St Paul Rd
[5] => Georges Guibert St
[6] => Curepipe
)
[distance] => 22.4
)
)
我用,
$ total = count($ array)-1; $ current = $ array [0] ['distance'];
for($loop=1;$loop<$total;$loop++){
$next = $array[$loop]['distance'];
$current = $next;
$current = $current;
if ($next>$current){
print_r($current);
}
}
}
获取所有键的索引,取第一个索引并使用交换将其与其他值进行比较..但它不起作用。有人有一个修复请。谢谢你
答案 0 :(得分:0)
如果我正确地理解了这一点,你不应该设置$ current = $ next,除非它在if语句中,并且它看起来你还有一个额外的}。我也相信你想改变你的&gt;到&lt;在你的if语句中。这样它就会告诉$ next是否是两者中的较小者。
试试这个:
for($loop=1;$loop<$total;$loop++){
$next = $array[$loop]['distance'];
if ($next<$current){
$current = $next;
print_r($current);
}
}
希望它可以帮助你!