Question

有没有办法将参数传递给SAX解析器。我按如下方式获得了解析器：

from xml.sax import make_parser, handler
class parserSAXHandler(handler.ContentHandler):

    def __init__(self):


    def startElement(self, name, attrs):

    def endElement(self,name):


    def characters(self, content):


parser = make_parser()
parser.setContentHandler(parserSAXHandler())

doc="PathToDocToBeParsed";
parser.parse(doc);

如何将参数传递给处理程序对象？

Answer 1

只需让你的__init__函数接受参数，并将这些参数存储到以后。

from xml.sax import make_parser, handler
class parserSAXHandler(handler.ContentHandler):

    def __init__(self, something):
        self.something = something

    def startElement(self, name, attrs):

    def endElement(self,name):
        ...
        do_something(self.something)
        ...

    def characters(self, content):


parser = make_parser()
parser.setContentHandler(parserSAXHandler(some_argument))

doc="PathToDocToBeParsed";
parser.parse(doc);

在python中将参数传递给SAX处理程序

1 个答案: