Question

使用这两个查询。在while循环中的第二个，我能够在表das上显示为行和小时作为列，以逐个小时地获得活动计数。这里的问题是，没有按小时显示每小时的活动，这应该在第二个查询中。请检查我的查询，如果您有任何疑问，请告诉我。该脚本显示de信息，但不按小时（0到23）显示。

$query = "SELECT DISTINCT month(timestamp), day(timestamp) AS days
          FROM security_transactions
     where timestamp <= getdate()
     order by month(timestamp), day(timestamp)";
     $result = odbc_exec($conn,$query);

$number_day = odbc_result($result,'days');
$query2 = "SELECT COUNT(id) as hours
          FROM security_transactions 
      WHERE MONTH(timestamp) = $month_count 
      AND DAY(timestamp) = $$number_day
      GROUP BY DATEPART(hh, timestamp)";

这个想法是有这样的一行：

天| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 12等等......

1月1日452 | 458 | 53 | 584 | 125 | 056 | 57 | 48 | 589 | 410 |等等...

Answer 1

我认为你没有理由做两个单独的查询。我会这样做一个查询：

SELECT count(*) as countof, year(timestamp) as years, month(timestamp) as months, day(timestamp) as days, hour(timestamp) as hours
FROM security_transactions
WHERE timestamp <= getdate()
GROUP BY years, months, days, hours

每个组合都会得到一行，因此您的前端代码只需要检测年/月/日组合何时发生变化，这可以通过简单的循环完成。

好的，有关php循环（未测试）的一些帮助

$sql = '...query';

$data = array();
while ($row = mysql_fetch_assoc($result)) {
  $daykey = $row['years'].'-'.$row['months'].'-'.$row['days'];
  if (!array_key_exists($daykey, $data)) {
     //prefill the hours
     $data[$daykey] = array_fill(0, 23, 0);
  }
  $data[$daykey][$row['hours'] = $row['countof'];
}
// Now you have array already setup with day/hours counts.  Also solves issue if hours don't have counts.
foreach ($data as $day => $hours) {
  //Output your day markup here
  foreach ($hours as $hour => $val) {
   // Output one hour value
   echo "$val |";
  }
  // close your day markup here (newline or whatever you're using)
}

我需要用php和mysql按天显示活动。下面是我失败的代码

1 个答案: