Question

我有一个REST服务，我希望有一个处理异常的辅助类

我的代码如下：

[WebGet(UriTemplate = "/Test/{param}")]
public Stream Test(string param)
{
        if (param == "Ok")
            return Process(param);
        else
        {
            RESTException(System.Net.HttpStatusCode.BadRequest, "Param not ok");
            return null;
        }
}


private void RESTException(System.Net.HttpStatusCode httpStatusCode, string message)
{
        OutgoingWebResponseContext response = WebOperationContext.Current.OutgoingResponse;
        response.StatusCode = httpStatusCode; // or anything you want
        response.StatusDescription = message;
}

我从浏览器测试，但是当我通过错误的参数时，例如

http://myaddress/Service/Test/badparam

浏览器中没有任何内容。

我的代码有什么问题？

Answer 1

更改

RESTException(System.Net.HttpStatusCode.BadRequest, "Param not ok");
return null;

到

RESTException(System.Net.HttpStatusCode.BadRequest, "Param not ok");
return "Param not ok";

Answer 2

我更改了RESTException，如下所示，当从浏览器或REST WCF WebApi提供的REST测试客户端测试REST时，抛出正确的异常并且slsdo显示正确的异常信息

    private void RESTException(SelectFault fault, System.Net.HttpStatusCode httpStatusCode)
    {
        throw new WebFaultException<string>(fault.ErrorMessage, httpStatusCode);
    }

REST服务中的异常处理

2 个答案: