Question

我在button1_Click（对象发送者，RoutedEventArgs e）中调用XamlReader.Load（）时得到XamlParseException，代码如下：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Data.SqlClient;
using System.Data;
using System.IO;
using HTMLConverter;
using System.Windows.Markup;


namespace StackoverflowTest
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public static SqlConnection conn = new SqlConnection("Server=" + @".\SQLEXPRE" +
                                    ";Initial Catalog=Hukuk;" +
                                    "Integrated Security=True;" +
                                    "User ID=;" +
                                    "Password=;");

        public MainWindow()
        {
            InitializeComponent();
            try
            {
                conn.Open();
            }
            catch (Exception ex)
            {
                MessageBox.Show("Error opening SQL Server connection\n" + ex.Message);
                //Close();
            }

        }

        public static FlowDocument SetRTF(string xamlString)
        {
            StringReader stringReader = new StringReader(xamlString);
            System.Xml.XmlReader xmlReader = System.Xml.XmlReader.Create(stringReader);
            return XamlReader.Load(xmlReader) as FlowDocument;
        }


        private void button1_Click(object sender, RoutedEventArgs e)
        {
            SqlCommand commProc = new SqlCommand("SELECT Name, Content from Document where ID=3219", MainWindow.conn);
            string str;
            FlowDocumentReader fdocr = new FlowDocumentReader();
            SqlDataReader dr = commProc.ExecuteReader();
            try
            {
                if (dr.Read())
                {
                    byte[] bt = (byte[])dr["Content"];
                    str = Encoding.Default.GetString(bt);
                    str = HTMLConverter.HtmlToXamlConverter.ConvertHtmlToXaml(str, true);
                    fdocr.Document = MainWindow.SetRTF(str);
                }
            }
            catch (Exception ex)
            {
                MessageBox.Show("An error occured while trying to view document\n" + ex.Message);
            }

            dr.Close();
            dr.Dispose();
        }
    }
}

不幸的是，我无法发布我试图通过的xamlstring，因为它太大了......有没有其他方法可以向你展示？

例外情况如下：

System.Windows.Markup.XamlParseException occurred
  Message='Add value to collection of type 'System.Windows.Documents.TableRowGroupCollection' threw an exception.' Line number '1' and line position '28143'.
  Source=PresentationFramework
  LineNumber=1
  LinePosition=28143
  StackTrace:
       at System.Windows.Markup.XamlReader.RewrapException(Exception e, IXamlLineInfo lineInfo, Uri baseUri)
       at System.Windows.Markup.WpfXamlLoader.Load(XamlReader xamlReader, IXamlObjectWriterFactory writerFactory, Boolean skipJournaledProperties, Object rootObject, XamlObjectWriterSettings settings, Uri baseUri)
       at System.Windows.Markup.WpfXamlLoader.Load(XamlReader xamlReader, Boolean skipJournaledProperties, Uri baseUri)
       at System.Windows.Markup.XamlReader.Load(XamlReader xamlReader, ParserContext parserContext)
       at System.Windows.Markup.XamlReader.Load(XmlReader reader, ParserContext parserContext, XamlParseMode parseMode)
       at System.Windows.Markup.XamlReader.Load(XmlReader reader)
       at WpfApplication1.MainWindow.SetRTF(String xamlString) in C:\Documents and Settings\nosirovkh\Рабочий стол\посл\WpfApplication1\WpfApplication1\WpfApplication1\MainWindow.xaml.cs:line 69
  InnerException: System.ArgumentNullException
       Message=Value cannot be null.
Parameter name: item
       Source=PresentationFramework
       ParamName=item
       StackTrace:
            at MS.Internal.Documents.TableTextElementCollectionInternal`2.Add(TElementType item)
            at MS.Internal.Documents.ContentElementCollection`2.System.Collections.IList.Add(Object value)
            at System.Windows.Documents.TableRowGroupCollection.System.Collections.IList.Add(Object value)
            at System.Xaml.Schema.XamlTypeInvoker.AddToCollection(Object instance, Object item)
            at MS.Internal.Xaml.Runtime.ClrObjectRuntime.Add(Object collection, XamlType collectionType, Object value, XamlType valueXamlType)
       InnerException:

Answer 1

看起来你的XAML可能是由某个程序生成的，这是问题的根源。

问题在于：

<Table>
  <TableColumn Width="331"/>
  <TableColumn Width="48"/>
  <TableColumn Width="48"/>
  <TableColumn Width="48"/>
  <TableColumn Width="48"/>
  <TableColumn Width="44"/>
  <TableColumn Width="52"/>
  ...
</Table>

这是正确的代码：

<Table>
  <Table.Columns>
    <TableColumn Width="331"/>
    <TableColumn Width="48"/>
    <TableColumn Width="48"/>
    <TableColumn Width="48"/>
    <TableColumn Width="48"/>
    <TableColumn Width="44"/>
    <TableColumn Width="52"/>
  </Table.Columns>
  ...
</Table>

有6个表格会发生这种情况。

我不知道是什么产生了这个XAML，但这似乎是一个坏错误。您可能需要修复它或自行修复XAML文件，可以通过编写一个小程序来查找这类内容，也可以手动使用（最好）Visual Studio。

Answer 2

使用以下xaml代码启动WPF应用程序时出现类似错误：

<Window x:Class="XXX.Wpf.IV.MainWindow"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="IV" WindowState="Normal" Height="1024" Width="1280">

<Grid>
    <local:IVView x:Name="_ivView"/> 
</Grid>

</Window>

原来导致“XmalParseException添加到集合...”的原因是我的IVView类应该是UserControl，但我创建它作为Window的扩展。我怀疑我们有类似的问题。

调用XamlReader.Load（xmlReader）时获取XamlParseException

2 个答案: