检索表中的重复项并显示它们

Question

我有下表，如果超过1行包含相同的'user_badge_name'和'user_email'，则认为是重复的。

user_id | user_name | user_badge_name | user_email
--------------------------------------------------
234     | Kylie     | ky001           | kylie@test.com
235     | Francois  | FR007           | france@test.com 
236     | Maria     | MA300           | Marie@test.com
237     | Francine  | FR007           | france@test.com 

我需要显示复制'user_badge_name'和'user_email'的那些行的user_ids和username。

我尝试了以下sql，但它没有返回所有user_ids，只返回第一个id

SELECT user_id, username , COUNT(user_badge_name) AS user_badge_name_Count FROM user GROUP BY user_badge_name HAVING user_badge_name_Count > 1

任何建议都表示赞赏

Answer 1

select a.user_id, a.user_name
from user as a
inner join
(SELECT user_badge_name, user_email
FROM user
GROUP BY user_badge_name, user_email
HAVING count(*)>1
) as dups
on a.user_badge_name=dups.user_badge_name and a.user_email=dups.user_email
order by a.user_badge_name, a.user_email

Answer 2

如果要查看同一行中的所有用户ID，则可以使用GROUP_CONCAT：

SELECT GROUP_CONCAT(user_id) AS user_ids, GROUP_CONCAT(username) AS usernames, COUNT(user_badge_name) AS user_badge_name_Count FROM user GROUP BY user_badge_name HAVING user_badge_name_Count > 1

那会给你这样的东西：

user_ids | usernames         | user_badge_name_Count
-----------------------------------------------
235,237  | Francois,Francine | 2