Facebook iOS SDK:如何获得用户的Facebook状态?

时间:2012-02-02 14:39:15

标签: objective-c facebook-ios-sdk

我使用Facebook iOS SDK参考非常困难,因为我不是专家编码员。我只是有这个简单的问题。

我知道以下代码为我提供了用户信息......

[facebook requestWithGraphPath:@"me" andDelegate:self];

但它去哪儿了?我可以说,如何获得用户的名字或状态并将其设置为标签的值?

如果有人写完答案的全部代码,我会感激万亿。

2 个答案:

答案 0 :(得分:2)

当您调用此方法时,这是SDK期望的内容:

  • 自我实现FBRequestDelegate
  • self有一个方法请求:didLoad

以下是一个快速代码示例:

---- MyClass.h BEGIN ----

#import <UIKit/UIKit.h>
#import "FBConnect.h"

@interface MyClass : NSObject <FBSessionDelegate, FBRequestDelegate>

@property (nonatomic, retain) Facebook *facebook;
@property (nonatomic, retain) NSString *userStatus;

@end

---- MyClass.h END ----

---- MyClass.m BEGIN ----

#import "MyClass.h"

@implementation MyClass

@synthesize facebook;
@synthesize userStatus;

- (id)init {
    self = [super init];

    if (self) {
        facebook = [[Facebook alloc] initWithAppId:@"App ID Here" andDelegate:self];
    }

    return self;
}

- (void)fbDidLogin {
    NSLog(@"Facebook logged in!");
    [facebook requestWithGraphPath:@"me" andDelegate:self];
}

- (void)request:(FBRequest *)request didLoad:(id)result {
    NSLog(@"Request loaded! Result: %@", result);
    SBJSON *parser = [[SBJSON alloc] init];
    NSDictionary *jsonResponse = [parser objectWithString:result error:nil];
    userStatus = [jsonResponse objectForKey:message];
    [parser release];

    NSLog(@"User's status message: %@", userStatus);
}

@end

---- MyClass.m END ----

希望这有帮助!

答案 1 :(得分:1)

Umair,

获取访问令牌后,您可以使用以下代码:

NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"https://graph.facebook.com/me?access_token=youracesstoken"]];

NSError *err = nil;

NSURLResponse *resp = nil;

NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:&resp error:&err];


if (resp != nil) {

    NSString *stringResponse = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];

    NSLog(@"stringResponse---%@",stringResponse);

    // stringResponse will be in JSON Format you need to use a JSON parser (Like SBJSON or TouchJSON)
}