Question

这是我的问题：

INPUT（来自某个网站）：

{"error":[],"results":{"count":2,"data":[{"ART_ID":"656","ART_NAME":"Noir D\u00e9sir","ART_PICTURE":".....","NB_ALBUM":"15","NB_FAN":"90176","SMARTRADIO":"1","URL_REWRITING":"noir-desir"},{"ART_ID":"167225","ART_NAME":"LMFAO","ART_PICTURE":"....","NB_ALBUM":"17","NB_FAN":"122408","SMARTRADIO":"1","URL_REWRITING":"lmfao"}],"total":2}}

所以，一旦我有了，我正在使用一些JSON类：

 NSError* jsonError = nil;
 //responseData contains my json feed
 NSDictionary* dict = [NSJSONSerialization JSONObjectWithData:responseData options:0 error:&jsonError];

 NSLog(@"responseDictionary : \n%@\n--------\n", [dict description]);

为了获得以下内容：

{
    error =     (
    );
    results =     {
        count = 2;
        data =         (
                        {
                "ART_ID" = 656;
                "ART_NAME" = "Noir D\U00e9sir";
                "ART_PICTURE" = 17b0a9c3defcf8c3eef943759606b3f4;
                "NB_ALBUM" = 15;
                "NB_FAN" = 90176;
                SMARTRADIO = 1;
                "URL_REWRITING" = "noir-desir";
            },
                        {
                "ART_ID" = 167225;
                "ART_NAME" = LMFAO;
                "ART_PICTURE" = 72a09b9202da38afae077e80c7598212;
                "NB_ALBUM" = 17;
                "NB_FAN" = 122408;
                SMARTRADIO = 1;
                "URL_REWRITING" = lmfao;
            }
        );
        total = 2;
    };
}

在这里，我真的没有任何问题......但是现在，我想获得这个NSDictionary中的“数据”字段。所以我只是创建一个新的：

NSDictionary* resultField = [NSDictionary dictionaryWithDictionary:[dict objectForKey:@"results"]];

包含：

{
    count = 2;
    data =     (
                {
            "ART_ID" = 656;
            "ART_NAME" = "Noir D\U00e9sir";
            "ART_PICTURE" = 17b0a9c3defcf8c3eef943759606b3f4;
            "NB_ALBUM" = 15;
            "NB_FAN" = 90176;
            SMARTRADIO = 1;
            "URL_REWRITING" = "noir-desir";
        },
                {
            "ART_ID" = 167225;
            "ART_NAME" = LMFAO;
            "ART_PICTURE" = 72a09b9202da38afae077e80c7598212;
            "NB_ALBUM" = 17;
            "NB_FAN" = 122408;
            SMARTRADIO = 1;
            "URL_REWRITING" = lmfao;
        }
    );
    total = 2;
}

现在我想得到我的“数据”字段，现在是JSONArray（不再是NSDictionary了......）：

NSArray* dataField = [[NSArray alloc] initWithArray:[dict objectForKey:@"data"]];

但之后我的dataField是空的......我的意思是这样：

NSArray* dataField = [[NSArray alloc] initWithArray:[dict objectForKey:@"data"]];
if (!dataField || ![dataField isKindOfClass:[NSArray class]]) {
    NSLog(@"Pb parsing DATA field as NSArray...");
}
NSLog(@"dataField : \n%@\n--------\n", [dataField description]);

不显示错误，因为它是格式正确的NSArray，但是打印出以下内容：

2012-02-02 14:08:52.315 myapp[5235:f803] dataField : 
(
)

我现在迷路了，我真的不知道发生了什么......如果你们对这个问题有任何线索，我很高兴你能帮助我！

由于

Answer 1

您正在从第一个字典（dict）中获取“数据”数组，您应该从resultField获取它：

NSArray* dataField = [[NSArray alloc] initWithArray:[resultField objectForKey:@"data"]];

NSSrray到NSArray的JSON给了我空的NSArray？ :(

1 个答案: