在模拟器上我测试应用程序并且它正在工作,但是当我穿上真正的设备继续告诉我:短信发送faild你想再试一次。 有些数字看起来像+381624578588或+ 38163-12-345-67,我也只尝试使用0629876543,并且总是相同的,这些都是例子,但我尝试了实数。 请帮忙。
这是我的sms方法代码:
private void sendPoruka(String ime2, String napisaniTekst2) {
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,new Intent(DELIVERED), 0);
//---when the SMS has been sent---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS sent", Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(getBaseContext(), "Generic failure", Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(getBaseContext(), "No service",Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(getBaseContext(), "Null PDU",Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(getBaseContext(), "Radio off", Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(SENT));
//---when the SMS has been delivered---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context context, Intent intent) {
// TODO Auto-generated method stub
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS delivered", Toast.LENGTH_SHORT).show();
break;
case Activity.RESULT_CANCELED:
Toast.makeText(getBaseContext(), "SMS not delivered",Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(DELIVERED));
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(ime2, null, napisaniTekst2, sentPI, deliveredPI);
}
答案 0 :(得分:2)
检查您是否在清单文件中获得了以下权限:
<uses-permission android:name="android.permission.SEND_SMS"/>
<uses-permission android:name="android.permission.RECEIVE_SMS" />