Question

我正在使用Oracle SQL 11g R2尝试以下字符串搜索：

数据是：

| CN = aXYZApple-Au，OU =托管，OU =组，DC =核心，DC = dir，DC = abc，DC = com | CN = 31107427，OU =分布列表，OU =共享邮箱，DC =核心，DC = dir，DC = abc，DC = com | CN = ea90045052，OU = Groups，OU = eProfile，DC = core，DC = dir，DC = abc，DC = com | CN = S0901448，OU =分布列表，OU =共享邮箱，DC =核心，DC = dir，DC = abc，DC = com | CN = 00900887，OU =分发列表，OU =共享邮箱，DC =核心，DC = dir，DC = abc，DC = com | CN = NSMMMM，OU = LRP，OU =组，DC =核心，DC = dir，DC = abc，DC = com | CN = aXYZApple-只读，OU =管理，OU =组，DC =芯，DC = DIR，DC = ABC，DC = com的 | CN = WWSWW-Au，OU = LRP，OU =组，DC =核心，DC = dir，DC = abc，DC = com | CN = aLogical_RW，OU =托管，OU =组，DC =核心，DC = dir，DC = abc，DC = com | CN = aXYZApple-Write，OU = Managed，OU = Groups，DC = core，DC = dir，DC = abc，DC = com |

从上面的数据中，我需要获取所有包含字符串“aXYZApple”的字符串，只有“OU = Managed”作为此字符串匹配的第二部分。

基于以上所述，以下结果就是我所追求的，并且只会显示：

aXYZApple-Au
aXYZApple-Readonly
aXYZApple-Write

使用的是Oracle regexp_like / regexp_replace。

Answer 1

您可以使用regexp_substr将输入数据拆分为行，然后查找相关字符串，例如：

SQL> SELECT regexp_substr(line, 'aXYZApple[^,]*') subtxt
  2    FROM (SELECT regexp_substr(:x, '[^|]*\|', 1, rownum + 1) line
  3             FROM dual
  4           CONNECT BY LEVEL <= length(:x) - length(REPLACE(:x, '|', '')))
  5   WHERE regexp_substr(line || ',', '[^,]*,', 1, 2) = 'OU=Managed,'
  6     AND line LIKE '%aXYZApple%';

SUBTXT
--------------------------------------------------------------------------------
aXYZApple-Au
aXYZApple-Readonly
aXYZApple-Write

这里有一点解释。您必须逐步完成查询。

查询的内部部分将遍历您的数据（对于每个|）：

SQL> SELECT regexp_substr(:x, '[^|]*\|', 1, rownum + 1) line
  2    FROM dual
  3  CONNECT BY LEVEL <= length(:x) - length(REPLACE(:x, '|', ''));

LINE
--------------------------------------------------------------------------------
 CN=aXYZApple-Au,OU=Managed,OU=Groups,DC=core,DC=dir,DC=abc,DC=com |
 CN=31107427,OU=Distribution Lists,OU=Shared Mailboxes,DC=core,DC=dir,DC=abc,DC=
 CN=ea90045052,OU=Groups,OU=eProfile,DC=core,DC=dir,DC=abc,DC=com |
 CN=S0901448,OU=Distribution Lists,OU=Shared Mailboxes,DC=core,DC=dir,DC=abc,DC=
 CN=00900887,OU=Distribution Lists,OU=Shared Mailboxes,DC=core,DC=dir,DC=abc,DC=
 CN=NSMMMM,OU=LRP,OU=Groups,DC=core,DC=dir,DC=abc,DC=com |
 CN=aXYZApple-Readonly,OU=Managed,OU=Groups,DC=core,DC=dir,DC=abc,DC=com |
 CN=WWSWW-Au,OU=LRP,OU=Groups,DC=core,DC=dir,DC=abc,DC=com |
 CN=aLogical_RW,OU=Managed,OU=Groups,DC=core,DC=dir,DC=abc,DC=com |
 CN=aXYZApple-Write,OU=Managed,OU=Groups,DC=core,DC=dir,DC=abc,DC=com |

然后，您将在第二个位置循环OU=Managed字符串：

SQL> SELECT regexp_substr(line || ',', '[^,]*,', 1, 2) second_part
  2    FROM (SELECT regexp_substr(:x, '[^|]*\|', 1, rownum + 1) line
  3             FROM dual
  4           CONNECT BY LEVEL <= length(:x) - length(REPLACE(:x, '|', '')));

SECOND_PART
--------------------------------------------------------------------------------
OU=Managed,
OU=Distribution Lists,
OU=Groups,
OU=Distribution Lists,
OU=Distribution Lists,
OU=LRP,
OU=Managed,
OU=LRP,
OU=Managed,
OU=Managed,

最后，选择最后regexp_substr的相关部分。

使用Oracle SQL检索字符串中的某些字符串

1 个答案: