Question

在我的应用程序中，我想看看Windows 7是否已激活。要清楚，我不想检查窗户是否是正品。我使用下面的代码http://www.dreamincode.net/forums/topic/166690-wmi-softwarelicensingproduct/

执行查询所需的时间约为5-10秒。反正有没有减少所需的时间？或者另一种检查winows 7是否被激活的方法？

public string VistaOrNewerStatus(){
string status = string.Empty;
string computer = ".";
try
{
    //set the scope of this search
    ManagementScope scope = new ManagementScope(@"\\" + computer + @"\root\cimv2");
    //connect to the machine
    scope.Connect();

    //use a SelectQuery to tell what we're searching in
    SelectQuery searchQuery = new SelectQuery("SELECT * FROM SoftwareLicensingProduct");

    //set the search up
    ManagementObjectSearcher searcherObj = new ManagementObjectSearcher(scope, searchQuery);

    //get the results into a collection
    using (ManagementObjectCollection obj = searcherObj.Get())
    {
        MessageBox.Show(obj.Count.ToString());
        //now loop through the collection looking for
        //an activation status
        foreach (ManagementObject o in obj)
        {

            //MessageBox.Show(o["ActivationRequired"].ToString());
            switch ((UInt32)o["LicenseStatus"])
            {
                case 0:
                    status = "Unlicensed";
                    break;
                case 1:
                    status = "Licensed";
                    break;
                case 2:
                    status = "Out-Of-Box Grace Period";
                    break;
                case 3:
                    status = "Out-Of-Tolerance Grace Period";
                    break;
                case 4:
                    status = "Non-Genuine Grace Period";
                    break;
            }
        }
    }


   // return activated;
}
catch (Exception ex)
{
   // MessageBox.Show(ex.ToString());
    status = ex.Message;
    //return false;
}
return status;

}

Answer 1

我建议只查询你真正需要的属性。因此，如果您只需要LicenseStatus WMI类的SoftwareLicensingProduct值，请使用以下查询：

SelectQuery searchQuery = new 
            SelectQuery("SELECT LicenseStatus FROM SoftwareLicensingProduct");

这可以改善您的表现。正如DJ KRAZE在答案中指出的那样，你当然应该处理你的管理课程。

在我的Windows 7计算机上，仅使用查询中的LicenseStatus属性 246ms 。查询所有属性（使用“*”）需要 2440ms 。

Answer 2

这通常是WMI工作的方式，它至少要查询..在下面你有以下内容..在你的foreach之后我将处理这些对象..

ManagementScope scope = new ManagementScope(@"\\" + computer + @"\root\cimv2");
//connect to the machine     
scope.Connect();      
//use a SelectQuery to tell what we're searching in
SelectQuery searchQuery = new SelectQuery("SELECT * FROM SoftwareLicensingProduct");
//set the search up     
ManagementObjectSearcher searcherObj

如果他们实现IDisposeable，那么你可以做

((IDisposable)scope).Dispose();
((IDisposable)searchQuery).Dispose();
((IDisposable)searcherObj).Dispose();

如果没有，则执行if（）以检查对象是否！= null然后单独处理它们尝试运行这几次，看看它是否会在处理完对象后返回得更快......除此之外......你可以做的不多，看起来更快......

Answer 3

我做的很快：）

 public bool IsLicensed(bool Licensed = false)
    {
        try
        {                
            foreach (ManagementObject Obj in new ManagementObjectSearcher("root\\CIMV2", "SELECT LicenseStatus FROM SoftwareLicensingProduct WHERE LicenseStatus = 1").Get())
            {
                Licensed = true;
            }
        }
        catch (ManagementException) { Licensed = false; }
        return Licensed;
    }

用法：

if(IsLicenced())
            MessageBox.Show("Windows is Licensed");

减少WMI查询执行时间

3 个答案: