Question

如何从Windows命令提示符获得总CPU使用率？：

预期产出：

27%

Answer 1

C:\> wmic cpu get loadpercentage
LoadPercentage
0

或者

C:\> @for /f "skip=1" %p in ('wmic cpu get loadpercentage') do @echo %p%
4%

Answer 2

以下命令提示符在Windows 7 Ultimate上正常运行：

C:\Windows\system32>typeperf "\Processor(_Total)\% Processor Time"

"(PDH-CSV 4.0)","\\vm\Processor(_Total)\% Processor Time"
"02/01/2012 14:10:59.361","0.648721"
"02/01/2012 14:11:00.362","2.986384"
"02/01/2012 14:11:01.364","0.000000"
"02/01/2012 14:11:02.366","0.000000"
"02/01/2012 14:11:03.367","1.038332"

The command completed successfully.

C:\Windows\system32>

或快照：

C:\Windows\system32>wmic cpu get loadpercentage
LoadPercentage
8

Answer 3

typeperf "\processor(_total)\% processor time"

适用于Win7，您只需要从最后一个引用的字符串中提取百分比值。

Answer 4

typeperf在某些计算机上随机无效（Error: No valid counters.）或帐户权限不足时，会向我提出问题。否则，这是一种从输出中仅提取值的方法。它仍然需要四舍五入：

@for /f "delims=, tokens=2" %p in ('typeperf "\Processor(_Total)\% Processor Time" -sc 3 ^| find ":"') do @echo %~p%

Powershell有两个cmdlet可以获得所有CPU的利用率百分比：Get-Counter（首选）或Get-WmiObject：

Powershell "Get-Counter '\Processor(*)\% Processor Time' | Select -Expand Countersamples | Select InstanceName, CookedValue"

或者，

Powershell "Get-WmiObject Win32_PerfFormattedData_PerfOS_Processor | Select Name, PercentProcessorTime"

使用格式化输出获得整体CPU负载，与问题完全相同：

Powershell "[string][int](Get-Counter '\Processor(*)\% Processor Time').Countersamples[0].CookedValue + '%'"

或者，

 Powershell "gwmi Win32_PerfFormattedData_PerfOS_Processor | Select -First 1 | %{'{0}%' -f $_.PercentProcessorTime}"

Answer 5

对于任何偶然浏览此页面的人，这里的解决方案都不适合我。我发现这是这样做的方法（在批处理文件中）：

@for /f "skip=1" %%p in ('wmic cpu get loadpercentage /VALUE') do (
   for /F "tokens=2 delims==" %%J in ("%%p") do echo %%J
)

从Windows命令提示符获取CPU使用率

5 个答案: