Question

我正在使用一个使用基本身份验证的REST Web服务，并返回一个XML字符串。这是我用来获取数据并将其作为XDocument返回的方法：

        var req = (HttpWebRequest)WebRequest.Create(uri);
        String readToEnd;
        const string postData = "";
        var encoding = new ASCIIEncoding();
        byte[] byte1 = encoding.GetBytes(postData);

        req.Method = "POST";
        req.Timeout = 10000;
        req.ContentType = "text/XML";
        req.ContentLength = byte1.Length;

        string authInfo = userName + ":" + password;

        authInfo = Convert.ToBase64String(Encoding.UTF8.GetBytes(authInfo));
        req.Headers["Authorization"] = "Basic " + authInfo;

        var newStream = req.GetRequestStream();
        newStream.Write(byte1, 0, byte1.Length);
        newStream.Close();

        try
        {
            var resp = req.GetResponse();
            var answer = resp.GetResponseStream();
            var _answer = new StreamReader(answer);
            readToEnd = _answer.ReadToEnd();
            answer.Close();
        }
        catch (Exception ex)
        {
            readToEnd = null;
        }

        return readToEnd != null ? XDocument.Parse(readToEnd) : null;

现在稍后，我操纵了那个xml，我准备把它发回给另一个uri。我认为它可能是相同的代码，除了可能将我的新XML字符串放在变量'postData'中？

这是将xml字符串发布到网络服务的正确方法吗？我已经看过了，但在使用基本授权时似乎无法对此有所了解。

Answer 1

我做了以下事情。关键是您必须在发布之前将数据写入请求流。希望它有所帮助。

 var request = CreateBaseRequest(body);
        HttpWebResponse WebResp = (HttpWebResponse)request.GetResponse();
        Stream Answer = WebResp.GetResponseStream();
        StreamReader response = new StreamReader(Answer);
        var r = response.ReadToEnd();

 static HttpWebRequest CreateBaseRequest(string postData)
    {

        var req = (HttpWebRequest)HttpWebRequest.Create(@"https://xyz.com/");

        req.ContentType = "application/x-www-form-urlencoded; charset=UTF-8";
        req.Method = "POST";
        req.KeepAlive = true;

        byte[] buffer = Encoding.ASCII.GetBytes(postData);

        req.ContentLength = buffer.Length;
        Stream PostData = req.GetRequestStream();
        PostData.Write(buffer, 0, buffer.Length);
        PostData.Close();

        return req;

    }

将XML提交给Rest Service时出现问题

1 个答案: