Question

我有一个形状为（4601,58）的numpy矩阵。
我想根据行数按60％，20％，20％的比例随机拆分矩阵
这是我需要的机器学习任务
是否存在随机选择行的numpy函数？

Answer 1

你可以使用numpy.random.shuffle

import numpy as np

N = 4601
data = np.arange(N*58).reshape(-1, 58)
np.random.shuffle(data)

a = data[:int(N*0.6)]
b = data[int(N*0.6):int(N*0.8)]
c = data[int(N*0.8):]

Answer 2

对于HYRY的答案的补充，如果你想要使用相同的第一维维度来调整几个数组x，y，z：x.shape[0] == y.shape[0] == z.shape[0] == n_samples。

你可以这样做：

rng = np.random.RandomState(42)  # reproducible results with a fixed seed
indices = np.arange(n_samples)
rng.shuffle(indices)
x_shuffled = x[indices]
y_shuffled = y[indices]
z_shuffled = z[indices]

然后按照HYRY的回答进行每个混洗数组的拆分。

Answer 3

如果要随机选择行，可以使用标准Python库中的random.sample：

import random

population = range(4601) # Your number of rows
choice = random.sample(population, k) # k being the number of samples you require

random.sample样本没有替换，因此您无需担心在choice中结束的重复行。给定一个名为matrix的numpy数组，您可以通过切片选择行，如下所示：matrix[choice]。

当然，k可以等于总体中元素的总数，然后choice将包含行的索引的随机排序。然后，您可以根据需要对choice进行分区，如果这就是您所需要的。

Answer 4

由于你需要它用于机器学习，这是我写的一个方法：

import numpy as np

def split_random(matrix, percent_train=70, percent_test=15):
    """
    Splits matrix data into randomly ordered sets 
    grouped by provided percentages.

    Usage:
    rows = 100
    columns = 2
    matrix = np.random.rand(rows, columns)
    training, testing, validation = \
    split_random(matrix, percent_train=80, percent_test=10)

    percent_validation 10
    training (80, 2)
    testing (10, 2)
    validation (10, 2)

    Returns:
    - training_data: percentage_train e.g. 70%
    - testing_data: percent_test e.g. 15%
    - validation_data: reminder from 100% e.g. 15%
    Created by Uki D. Lucas on Feb. 4, 2017
    """

    percent_validation = 100 - percent_train - percent_test

    if percent_validation < 0:
        print("Make sure that the provided sum of " + \
        "training and testing percentages is equal, " + \
        "or less than 100%.")
        percent_validation = 0
    else:
        print("percent_validation", percent_validation)

    #print(matrix)  
    rows = matrix.shape[0]
    np.random.shuffle(matrix)

    end_training = int(rows*percent_train/100)    
    end_testing = end_training + int((rows * percent_test/100))

    training = matrix[:end_training]
    testing = matrix[end_training:end_testing]
    validation = matrix[end_testing:]
    return training, testing, validation

# TEST:
rows = 100
columns = 2
matrix = np.random.rand(rows, columns)
training, testing, validation = split_random(matrix, percent_train=80, percent_test=10) 

print("training",training.shape)
print("testing",testing.shape)
print("validation",validation.shape)

print(split_random.__doc__)

训练（80,2）
测试（10,2）
验证（10,2）

Numpy：如何将矩阵随机分割/选择为n个不同的矩阵

4 个答案: