Question

我正在尝试构建一个查询，显示聚合列中值最高的行“NumberOfArticles”。但是，由于有多个行具有相同的最高值，因此我不确定如何正确限制查询生成的行数。

SELECT WRT_ID, COUNT(ART_ID) AS NumberOfArticles
FROM Articles
GROUP BY WRT_ID
ORDER BY NumberOfArticles DESC

Answer 1

我认为这对你来说已经足够了

SELECT WRT_ID, max(ART_ID) AS NumberOfArticles
FROM Articles
GROUP BY NumberOfArticles
ORDER BY NumberOfArticles DESC

Answer 2

SELECT TOP 1 WRT_ID, COUNT(ART_ID) AS NumberOfArticles
FROM Articles
GROUP BY WRT_ID
ORDER BY 2 DESC

如果有多个NumberOfArticles计数最高的行，则会包含关系。如果您不希望包含绑定，但只有一个具有最高NumberOfArticles计数的绑定，请将GROUP BY放在子查询中并根据需要更改ORDER BY。

SELECT TOP 1 sub.WRT_ID, sub.NumberOfArticles
FROM (
    SELECT WRT_ID, COUNT(ART_ID) AS NumberOfArticles
    FROM Articles
    GROUP BY WRT_ID
    ) AS sub
ORDER BY 2 DESC, 1 DESC;

Answer 3

我想你可能想要：

SELECT A.WRT_ID, (SELECT MAX(B.ART_ID) FROM Articles As B WHERE B.WRT_ID = A.WRT_ID) As NumberOfArticles
FROM Articles A
ORDER BY 2 Desc

这使用子选择来获得每个Wrt_Id

的最高Art_Id

我看到你在你的样本中使用了COUNT，虽然问题提示更多的是最大值，但如果它是计数，那么你只需修改为：

SELECT A.WRT_ID, (SELECT COUNT(B.ART_ID) FROM Articles As B WHERE B.WRT_ID = A.WRT_ID) As NumberOfArticles
FROM Articles A
ORDER BY 2 Desc

Answer 4

SELECT WRT_ID, COUNT(ART_ID) AS NumberOfArticles
FROM Articles
GROUP BY WRT_ID
HAVING COUNT(ART_ID)=(SELECT MAX(t.c) FROM ( SELECT WRT_ID,COUNT(ART_ID) AS c 
                                             FROM Articles GROUP BY WRT_ID ) t )
ORDER BY NumberOfArticles DESC

这为您提供了所有最大行数。

显示具有最大聚合值的查询结果

4 个答案: