Question

在我的应用程序中，我有一个System.Timers.Timer，它会在几毫秒后再次触发。

计时器声明：

mRecipeTimer = new System.Timers.Timer(30000);
mRecipeTimer.Start();
mRecipeTimer.Elapsed += new ElapsedEventHandler(mRecipeTimer_Elapsed);

计时器过去事件：

void mRecipeTimer_Elapsed(object sender, ElapsedEventArgs e)
{
    int sync = Interlocked.CompareExchange(ref syncPoint, 1, 0);
    if (sync == 0)
    {
        Thread.CurrentThread.Name = string.Format("timer, started at {0} ({1})", DateTime.Now, DateTime.Now.Millisecond);
        Log.Info("Recipe timer elapsed.");
        // some code
        syncPoint = 0;
    }
}

这就是我在日志中看到的内容：

2012-01-31 11:17:26,797 [timer, started at 1/31/2012 11:17:26 AM (797)] INFO  - Recipe timer elapsed.
2012-01-31 11:17:27,875 [timer, started at 1/31/2012 11:17:27 AM (875)] INFO  - Recipe timer elapsed.
2012-01-31 11:17:56,797 [timer, started at 1/31/2012 11:17:56 AM (797)] INFO  - Recipe timer elapsed.
2012-01-31 11:17:57,875 [timer, started at 1/31/2012 11:17:57 AM (875)] INFO  - Recipe timer elapsed.

我已经放置了一个互锁装置，这样只有一个动作可以同时运行。但不幸的是，计时器两次发射它的事件，我不知道为什么。

Answer 1

您可以在处理事件时始终禁用/启用计时器，即

void mRecipeTimer_Elapsed(object sender, ElapsedEventArgs e)
{
    mRecipeTimer.Enabled = false; //<---- disable

    int sync = Interlocked.CompareExchange(ref syncPoint, 1, 0);
    if (sync == 0)
    {
        Thread.CurrentThread.Name = string.Format("timer, started at {0} ({1})", DateTime.Now, DateTime.Now.Millisecond);
        Log.Info("Recipe timer elapsed.");
        // some code
        syncPoint = 0;
    }

    mRecipeTimer.Enabled = true; //<---- enable
}

System.Timers.Timer在几毫秒后第二次触发

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