我给你发了一个我想做的例子,用这种方式更容易解释
void myPrinter(const char* text, int number){
printf("\n%s %d\n", text, number);
}
int main() {
char *someText="test";
boost::function<void(int my_number)> functionWithSavedArgs = boost::bind(&myPrinter, someText, ?????);
//then I have to call my function with saved args and give to it only variable "number" like:
int myBeautifulNumber = 2012;
functionWithSavedArgs(myBeautifulNumber);
// echo: test 2012
}
有什么想法吗?
答案 0 :(得分:2)
跳过那个论点。
boost::function<void(int my_number)> functionWithSavedArgs
= boost::bind(&myPrinter, someText);
这只会绑定第一个参数。
如果您只想绑定第二个,则需要一个占位符:
boost::function<void(int my_number)> functionWithSavedArgs
= boost::bind(&myPrinter, _1, someNumber);