Question

调用followLink时，我得到了错误的访问权限。如果我将openURL行粘贴到textContainsURL中，这不会发生，所以我假设一旦方法完成后对象不再存在？我是新手，但我虽然ARC应该为你处理这类事情？

@interface MyViewController : UIViewController
{   
NSURL *newsURL;
}

@end

以下是在实施中：

- (void)followLink
{ 
    [[UIApplication sharedApplication]openURL:newsURL];

}

- (BOOL)textContainsURL:(NSString*)text
{
    NSError *error = NULL;
    //scan text to see if there is a link and only set this up if there is
    NSDataDetector *detector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeLink error:&error];

    NSArray *matches = [detector matchesInString:text
                                     options:0
                                       range:NSMakeRange(0, [text length])];

    for (NSTextCheckingResult *match in matches) 
    {
        //NSRange matchRange = [match range];
        if ([match resultType] == NSTextCheckingTypeLink) 
        {
            newsURL = [[NSURL alloc] init];
            newsURL = [match URL];//what's the void state? retain it
            return YES;
        }
    }

    return NO;
}

Answer 1

您应该将匹配的网址复制到您的newsURL ivar或将您的newsURL ivar复制属性并通过访问者方法设置值。在您当前的代码中，该URL是自动释放的。

为什么这段代码给了我EXC_BAD_ACCESS？

1 个答案: