基本上,我需要扫描它(来自输入.txt文件):
oooooooo
#S#ooooo
oo#oo##o
ooo#ooo#
oo#oo$oo
o######o
oooooooo
进入二维数组。这是我到目前为止所做的:
public static void main(String[] args) throws IOException
{
Scanner scan = new Scanner(new File("inputFile.txt"));
numRows = scan.nextInt();
numColumns = scan.nextInt();
mazeArray = new char[numRows][numColumns];
for(int row = 0; row < numRows; row++)
{
strings = scan.next();
for(int column = 0; column < numColumns; column++)
{
mazeArray[row][column] = strings.charAt(row);
System.out.print(mazeArray[row][column]);
}
System.out.print("\n");
}
}
输出完全错误:
oooooooo
SSSSSSSS
########
########
oooooooo
########
oooooooo
答案 0 :(得分:5)
// Change row -> column
mazeArray[row][column] = strings.charAt(column);
答案 1 :(得分:0)
System.out.println()
将始终打印一个新行。相反,您应该使用System.out.print()
并在每行后打印换行符“\ n”。
试试这个:
for(int row = 0; row < numRows; row++)
{
strings = scan.next();
for(int column = 0; column < numColumns; column++)
{
mazeArray[row][column] = strings.charAt(row);
System.out.print(mazeArray[row][column]);
}
System.out.print("\n");
}