我正在使用java中的一个简单的tcp聊天服务器。用户可以输入“push:”,“get”,“adios”,“help”等命令。 。 。我通过设置String Line = input.readLine()来检查这些用户命令(如下所示)。问题是当我输入“push:”时,我必须转到新行以获取新输入并将其分配给新字符串。我希望能够在用户键入命令后在同一行上获得输入。
例如:如果USER 1输入“push:”+“你好,你今天好吗?”我想存储“您好,今天好吗?”到一个数组,以便我以后可以打印它的内容。但是就像现在一样,我必须输入“push:”进入一个新行并输入“你好,今天你好吗?”将它存储到数组中。那太尴尬了。有没有办法将输入存储到同一行的两个不同的字符串?
这是我的服务器代码,请查看运行方法
// Chat Server runs at port no. 9020
import java.io.*;
import java.util.*;
import java.net.*;
import static java.lang.System.out;
public class TCPServer
{
Vector<String> users = new Vector<String>();
Vector<HandleClient> clients = new Vector<HandleClient>();
Vector<String> Chat = new Vector<String>();
int PORT = 9020;
int NumClients = 10;
public void process() throws Exception
{
ServerSocket server = new ServerSocket(PORT,NumClients);
out.println("Server Connected...");
while(true)
{
Socket client = server.accept();
HandleClient c = new HandleClient(client);
clients.add(c);
} // end of while
}
public static void main(String ... args) throws Exception
{
new TCPServer().process();
} // end of main
public void boradcast(String user, String message)
{
System.out.println(user + ": " + message);
// send message to all connected users
for (HandleClient c : clients)
if (!c.getUserName().equals(user))
{
c.sendMessage(user,message);
}
}
class HandleClient extends Thread
{
String name = "";
BufferedReader input;
PrintWriter output;
public HandleClient(Socket client) throws Exception
{
// get input and output streams
input = new BufferedReader(new InputStreamReader(client.getInputStream())) ;
output = new PrintWriter (client.getOutputStream(),true);
output.println("Welcome to Alan's Chat Server!\n");
// read name
output.println("Please Enter a User Name: ");
name = input.readLine();
users.add(name); // add to vector
output.println("\nWelcome "+name+" we hope you enjoy your chat today");
start();
}
public void sendMessage(String uname,String msg)
{
output.println( uname + ": " + msg);
}
public String getUserName()
{
return name;
}
public void run()
{
String line;
try
{
while(true)
{
line = input.readLine();
line.toLowerCase();//check this
if("adios".equals(line))
{
output.println("\nClosing Connection . . . Goodbye");
clients.remove(this);
users.remove(name);
break;
}
else if(name.equals(line))
{
output.println("OK");
}
else if("help".equals(line))
{
output.println("\nServer Commands:" + "\n\"audios:\" close the client connection\n"+
"\"Name:\" display \"OK\"\n");//Check this
}
else if("push: ".equals(line))
{
String NewLine = input.readLine();
Chat.add(NewLine);
output.println("OK");
}
else if("get".equals(line))
{
output.println(Chat.toString());
}
else
{
boradcast(name,line); // method of outer class - send messages to all
}
}// end of while
} // try
catch(Exception e)
{
System.out.println(e.getMessage());
}
} // end of run()
} // end of inner class
} // end of Server
答案 0 :(得分:1)
line = input.readLine();
line.toLowerCase();//check this
....
else if("push: ".equals(line))
.....
应该是
line = input.readLine();
String command = line.split(":")[0];
String otherStuff = line.split(":")[1];
command.toLowerCase();//check this
....
if("push".equals(command));
.....
答案 1 :(得分:1)
可能使用String.split("")
或使用StringTokenizer
类
String line = input.read();
String [] d = s.split(":",2);
通过数组索引访问值;
修改 :
为了清楚起见,我在split方法中传递了2作为第二个参数,因为它限制了将数组拆分为两个索引,所以你没有3个这样的数组:
String.split("PUSH: I am hungry :P");
因为它会输出[PUSH;我饿了; P]