Apache Poi - 如何从Word文档中删除所有链接

时间:2012-01-30 17:20:22

标签: java apache-poi hwpf xwpf

我想删除Word文档的所有超链接并保留文本。我有这两种方法来阅读带有doc和docx扩展名的word文档。

private void readDocXExtensionDocument(){
    File inputFile = new File(inputFolderDir, "test.docx");
    try {
        XWPFDocument document = new XWPFDocument(OPCPackage.open(new   FileInputStream(inputFile)));
        XWPFWordExtractor extractor = new XWPFWordExtractor(document);
        extractor.setFetchHyperlinks(true);
        String context =  extractor.getText();
        System.out.println(context);
    } catch (InvalidFormatException e) {
        e.printStackTrace();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

}

private void readDocExtensionDocument(){
    File inputFile = new File(inputFolderDir, "test.doc");
    POIFSFileSystem fs;
    try {
        fs = new POIFSFileSystem(new FileInputStream(inputFile));
        HWPFDocument document = new HWPFDocument(fs);
        WordExtractor wordExtractor = new WordExtractor(document);
        String[] paragraphs = wordExtractor.getParagraphText();
        System.out.println("Word document has " + paragraphs.length + " paragraphs");
        for(int i=0; i<paragraphs.length; i++){
            paragraphs[i] = paragraphs[i].replaceAll("\\cM?\r?\n", "");
            System.out.println(paragraphs[i]);
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
}

是否可以使用apache poi库删除word文档的所有链接?如果不是,是否还有其他库可以提供此功能?

1 个答案:

答案 0 :(得分:2)

至少对于.docx类别,我的解决方案是使用正则表达式。检查一下

private void readDocXExtensionDocument(){
   Pattern p = Pattern.compile("\\<(.+?)\\>");
   File inputFile = new File(inputFolderDir, "test.docx");
   try {
      XWPFDocument document = new XWPFDocument(OPCPackage.open(new   FileInputStream(inputFile)));
      XWPFWordExtractor extractor = new XWPFWordExtractor(document);
      extractor.setFetchHyperlinks(true);
      String context =  extractor.getText();
      Matcher m = p.matcher(context);
      while (m.find()) {
         String link = m.group(0); // the bracketed part
         String textString = m.group(1); // the text of the link without the brackets
         context = context.replaceAll(link, ""); // ordering important.  Link then textString
         context = context.replaceAll(textString, "");
      }
      System.out.println(context);
   } catch (InvalidFormatException e) {
    e.printStackTrace();
   } catch (FileNotFoundException e) {
    e.printStackTrace();
   } catch (IOException e) {
    e.printStackTrace();
   }
  }

这种方法的唯一警告是,如果有这些带角度的支架的材料不是链接,那么也可以删除。如果您更好地了解可能出现的链接类型,您可以尝试使用更具体的正则表达式而不是我提供的正则表达式。