Question

我a small card game for Google+需要访客的姓名，头像，性别和城市。

它适用于我自己，但在error_log中我看到很多PHP例外：

[28-Jan-2012 19:06:33] PHP Fatal error:  Uncaught exception 'apiServiceException' with message 'Error calling GET https://www.googleapis.com/plus/v1/people/me?alt=json&key=AIzaSyAgQl0UeNM553PfLnPmP0jTtcJ8ZIQ3q0g: (404) Not Found' in /var/www/html/preferans.de/google/google-api-php-client/src/io/apiREST.php:86
Stack trace:
#0 /var/www/html/preferans.de/google/google-api-php-client/src/io/apiREST.php(56): apiREST::decodeHttpResponse(Object(apiHttpRequest))
#1 /var/www/html/preferans.de/google/google-api-php-client/src/service/apiServiceResource.php(151): apiREST::execute(Object(apiServiceRequest))
#2 /var/www/html/preferans.de/google/google-api-php-client/src/contrib/apiPlusService.php(207): apiServiceResource->__call('get', Array)
#3 /var/www/html/preferans.de/google/index.php(33): PeopleServiceResource->get('me')
#4 {main}
  thrown in /var/www/html/preferans.de/google/google-api-php-client/src/io/apiREST.php on line 86

这是我的剧本：

<?php

require_once('google-api-php-client/src/apiClient.php');
require_once('google-api-php-client/src/contrib/apiPlusService.php');

session_start();

$client = new apiClient();
$client->setApplicationName('Video-Preferans');
$client->setClientId('XXX.apps.googleusercontent.com');
$client->setClientSecret('XXX');
$client->setRedirectUri('http://preferans.de/google');
$client->setDeveloperKey('XXX');
$client->setScopes(array('https://www.googleapis.com/auth/plus.me'));
$plus = new apiPlusService($client);

if (isset($_REQUEST['logout']))
        unset($_SESSION['access_token']);

if (isset($_GET['code'])) {
        $client->authenticate();
        $_SESSION['access_token'] = $client->getAccessToken();
        header('Location: http://' . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF']);
}

if (isset($_SESSION['access_token']))
        $client->setAccessToken($_SESSION['access_token']);

if ($client->getAccessToken()) {
        $me = $plus->people->get('me'); # XXX line 33 XXX
        # the access token may have been updated lazily
        $_SESSION['access_token'] = $client->getAccessToken();
} else {
        printf('
<!doctype html>
<html>
<head>
<body>
<p><a href="%s">Play Preferans</a></p>
</body>
</html>
', $client->createAuthUrl());
        exit();
}

$viewer_id = $me['id'];
list($first_name, $last_name) = explode(' ', $me['displayName']);
$city      = $me['placesLived'][0]['value'];
$female    = ($me['gender'] == 'male' ? 0 : 1);
$avatar    = $me['image']['url'];

....skipped some html code....

有人请知道，为什么抛出 apiServiceException ？

或者至少如何以及在哪里捕获它，以便我可以更好地调试它？

我正在使用the latest Google+ SDK 0.4.8.3并且我正在请求非常基本的用户信息，正如我所写的那样 - 它适用于我和我妻子的帐户。

Answer 1

你可以在try / catch块中包装$ me = $ plus-＆gt; people-＆gt; get（'me'）。

当用户尚未注册Google+时，plus / v1 / people / me API会返回404 Not Found，您可以通过以下方式查看此案例：

try {
   $me = $plus->people->get('me')
} catch (apiServiceException $e) {
  // Handle exception. You can also catch Exception here.
  // You can also get the error code from $e->getCode();
}

Answer 2

我遇到同样的问题，唯一的区别是我正在尝试使用Calendar API。我得到了与你在第一时间完全相同的错误响应，尝试了try / catch-block，它有点工作。如果我打印错误响应它会显示“403”，但我也得到了我想要的JSON响应。你知道为什么吗？

我的代码：

if ($client->getAccessToken()) {
    try{
        $activities = $plus->activities->listActivities('me', 'public');
        print 'Your Activities: <pre>' . print_r($activities, true) . '</pre>';

        // The access token may have been updated.
        $_SESSION['token'] = $client->getAccessToken();
    } catch (apiServiceException $e) {
      // Handle exception. You can also catch Exception here.
      // You can also get the error code from $e->getCode();
        echo $e->getCode();
        print_r($activities);
    }

}

未捕获的异常'apiServiceException'，消息'Error calling GET ....'

2 个答案: