Question

获取表示当天午夜的NSDate对象的最有效方法是什么？

Answer 1

iOS 8中的新API

iOS 8在NSCalendar上包含一个名为 startOfDayForDate 的新方法，它非常易于使用：

let startOfToday = NSCalendar.currentCalendar().startOfDayForDate(NSDate())

Apple的描述：

此API返回给定日期的第一个时刻日期。例如，如果您想要“今天”的开头，请传入[NSDate日期]。如果有两个中午，则返回第一个。如果没有，则返回确实存在的第一个时刻。

更新，关于时区：

由于startOfDayForDate是NSCalendar上的一种方法，因此它使用NSCalendar的时区。所以，如果我想知道它在纽约的时间，那么今天在洛杉矶开始时，我可以这样做：

let losAngelesCalendar = NSCalendar.currentCalendar().copy() as! NSCalendar
losAngelesCalendar.timeZone = NSTimeZone(name: "America/Los_Angeles")!

let dateTodayBeganInLosAngeles = losAngelesCalendar.startOfDayForDate(NSDate())
dateTodayBeganInLosAngeles.timeIntervalSince1970

let dateFormatter = NSDateFormatter()
dateFormatter.dateStyle = .MediumStyle
dateFormatter.timeStyle = .ShortStyle
dateFormatter.timeZone = NSTimeZone(name: "America/New_York")!
let timeInNewYorkWhenTodayBeganInLosAngeles = dateFormatter.stringFromDate(dateTodayBeganInLosAngeles)
print(timeInNewYorkWhenTodayBeganInLosAngeles) // prints "Jul 29, 2015, 3:00 AM"

Answer 2

试试这个：

NSDate *const date = NSDate.date;
NSCalendar *const calendar = NSCalendar.currentCalendar;
NSCalendarUnit const preservedComponents = (NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay);
NSDateComponents *const components = [calendar components:preservedComponents fromDate:date];
NSDate *const normalizedDate = [calendar dateFromComponents:components];

Answer 3

NSCalendar *cal = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease]; 
[cal setTimeZone:[NSTimeZone systemTimeZone]];  

 NSDateComponents * comp = [cal components:( NSYearCalendarUnit| NSMonthCalendarUnit | NSDayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit) fromDate:[NSDate date]]; 

 [comp setMinute:0]; 
 [comp setHour:0];
 [comp setSecond:0]; 

 NSDate *startOfToday = [cal dateFromComponents:comp];

如果您指的是午夜时间为23:59，则将组件的小时设置为23，将分钟设置为59。

Answer 4

您可以使用以下方法获取NSDate的午夜值。

- (NSDate *)dateAtBeginningOfDayForDate:(NSDate *)inputDate
{
    // Use the user's current calendar and time zone
    NSCalendar *calendar = [NSCalendar currentCalendar];
    NSTimeZone *timeZone = [NSTimeZone systemTimeZone];
    [calendar setTimeZone:timeZone];

    // Selectively convert the date components (year, month, day) of the input date
    NSDateComponents *dateComps = [calendar components:NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:inputDate];

    // Set the time components manually
    [dateComps setHour:0];
    [dateComps setMinute:0];
    [dateComps setSecond:0];

    // Convert back       
    NSDate *beginningOfDay = [calendar dateFromComponents:dateComps];
    return beginningOfDay;
}

Thkis取自website。

Answer 5

夫特：

let cal = NSCalendar.currentCalendar()

//tip:NSCalendarUnit can be omitted, but with the presence of it, you can take advantage of Xcode's auto-completion
var comps = cal.components(NSCalendarUnit.YearCalendarUnit | .MonthCalendarUnit | .DayCalendarUnit | .HourCalendarUnit | .MinuteCalendarUnit | .SecondCalendarUnit, fromDate: NSDate()) 
comps.hour = 0
comps.minute = 0
comps.second = 0

let midnightOfToday = cal.dateFromComponents(comps)!

Swift 2.2：

let cal = NSCalendar.currentCalendar()

let comps = cal.components([.Year, .Month, .Day, .Hour, .Minute, .Second], fromDate: NSDate())
comps.hour = 0
comps.minute = 0
comps.second = 0

let midnightOfToday = cal.dateFromComponents(comps)!

目标-C：

NSCalendar *cal = [NSCalendar currentCalendar]; 

NSDateComponents *comps = [cal components:(NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay | NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:[NSDate date]];    
[comps setHour:0]; 
[comps setMinute:0]; 
[comps setSecond:0];

NSDate *midnightOfToday = [cal dateFromComponents:comps];

Answer 6

从iOS8开始，您可以使用startDayForDate。

所以，为了获得今天的开始（目标-C）：

NSDate * midnight;
 midnight = [[NSCalendar currentCalendar] startOfDayForDate: [NSDate date]];

Answer 7

试试这个：

NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *now = [NSDate date];
NSDateComponents *components = [gregorian components:NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit fromDate:now];
NSDateFormatter* df = [[NSDateFormatter alloc]init];
[df setDateFormat:@"MM/dd/yyyy HH:mm:ss.SSS"];
NSLog(@"%@",[df stringFromDate:[gregorian dateFromComponents:components]]);

Answer 8

NSDate *now = [NSDate date];
NSDate *beginningOfToday = nil;
[[NSCalendar currentCalendar] rangeOfUnit:NSDayCalendarUnit startDate:&beginningOfToday interval:NULL forDate:now];

Answer 9

    let calendar = NSCalendar.currentCalendar()
    let unitFlags: NSCalendarUnit = [.Year, .Month, .Day, .Minute, .Second]
    let components = calendar.components(unitFlags , fromDate: NSDate())

    components.hour = 0
    components.minute = 0
    components.second = 0

    //Gives Midnight time of today
    let midnightOfToday = calendar.dateFromComponents(components)!

Answer 10

您可以使用 NSCalendar ＆＃39; dateBySettingHour:minute:second:ofDate:options:

所以这就像做：

NSCalendar *calendar = [NSCalendar currentCalendar];
calendar.timeZone = [NSTimeZone timeZoneWithName:@"UTC"];

NSDate *midnight = [calendar dateBySettingHour:0 minute:0 second:0 ofDate:[NSDate date] options:0];

今天午夜如何获得NSDate对象？

10 个答案: