我正在尝试使用ActiveRecord在Rails中进行查询,该查询指定了连接表上的某些条件。我似乎无法让它工作,即使我按照这里的例子:
http://guides.rubyonrails.org/active_record_querying.html#specifying-conditions-on-the-joined-tables
来自guides:
Client.joins(:orders).where(:orders => {:created_at => time_range})
我的数据库架构如下所示,包含表scores
,submissions
和tasks
:
create_table "scores", :force => true do |t|
t.integer "value"
t.integer "user_id"
t.datetime "created_at"
t.datetime "updated_at"
end
add_index "scores", ["user_id"], :name => "index_scores_on_user_id"
create_table "submissions", :force => true do |t|
t.integer "user_id"
t.integer "task_id"
t.integer "score_id"
t.datetime "completed_at"
t.datetime "created_at"
t.datetime "updated_at"
end
add_index "submissions", ["score_id"], :name => "index_submissions_on_score_id"
add_index "submissions", ["task_id"], :name => "index_submissions_on_task_id"
add_index "submissions", ["user_id"], :name => "index_submissions_on_user_id"
create_table "tasks", :force => true do |t|
t.integer "episode_id"
t.integer "score"
t.string "key"
t.datetime "created_at"
t.datetime "updated_at"
end
所以我想做一个查询,在那里我可以找到与特定任务有关的所有“分数”。提交属于任务和分数。
我的查询现在看起来像这样:
Score.joins(:submission).where(:submission => {:task_id => 1})
这会生成以下语法:
SELECT "scores".* FROM "scores" INNER JOIN "submissions" ON "submissions"."score_id" = "scores"."id" WHERE "submission"."task_id" = 1
会产生以下错误:
SQLite3::SQLException: no such column: submission.task_id
但是有一个列submission.task_id
,您可以在db模式中看到它。我可以成功地做到这一点:
SELECT "submissions".* FROM "submissions" WHERE "submissions"."task_id" = 1
答案 0 :(得分:62)
子句中的名称应为复数以引用表名:
Score.joins(:submission).where(:submissions => {:task_id => 1})
答案 1 :(得分:7)
子句名称应为复数以引用表名。
Score.joins(:submission).where(submissions: { task_id: 1 })
如果分数有很多提交,则连接符号也应该是复数,以引用分数和提交之间的关系。
Score.joins(:submissions).where(submissions: { task_id: 1 })
答案 2 :(得分:4)
警告:如果您使用非标准表名,上述内容将会失败:
ActiveRecord::StatementInvalid: PG::UndefinedTable: ERROR: missing FROM-clause entry for table "submissions"
要解决此问题,请将(joined-model-class).table_name
作为密钥放在where
哈希:
Score.joins(:submission).where(
Submission.table_name => {task_id: 1}
)
答案 3 :(得分:3)
我发现这更容易。
Score.joins(:submission).merge(Submission.where(task_id: 1))
答案 4 :(得分:1)
您的查询如下所示:
Score.joins(:submission).where(:submission => { :task_id => 1 })
您的#joins
是正确的,但:submission
应为复数:
Score.joins(:submission).where(:submissions => { :task_id => 1 })