Question

在编译它时在Bluej中编写了一个简短的java程序并尝试让它运行它，它没有输出就挂起了。我在使用in.next函数之前遇到过这个问题。关心任何帮助，并为看似简单的问题道歉。

import java.util.Scanner;

public class net_salary{

public static void main(String[]args){

Scanner in = new Scanner(System.in);



float income;
float incometax;
float afterincometax;
float nationalinsurance;
float afterni;
float pension;
float netincome;

income = in.nextFloat();





if(income <9000)
    {
      incometax = 0;
      afterincometax = income - incometax;

    }
    else if (income >=9000 && income <=21000)
    {
        incometax = (income * 0.15F);
        afterincometax = income - incometax;
    }

    else if (income >=21000 && income<=31000)
    {
        incometax = income * 0.2F;
        afterincometax = income - incometax;

    }

    else if (income >=31000 &&  income<=50000)
    {
        incometax = income * 0.225F;
        afterincometax = income - incometax;
    }

    else
    {
        incometax = income * 0.25F;
        afterincometax = income - incometax;
    }





   if(income < 16000)

   {
       nationalinsurance = 0;
       afterni = income - nationalinsurance;

    }


    else if(income >= 16000 && income <= 31000)
        {

            nationalinsurance = income*0.05F;
            afterni = income - nationalinsurance;
        }
    else if(income > 31000 && income <=40000)
        {

            nationalinsurance = income*0.09F;
            afterni = income - nationalinsurance;
        }
    else
        {

            nationalinsurance = income*0.11F;
            afterni = income - nationalinsurance;
        }





   pension = income *0.05F;

   netincome = ((income - pension)-nationalinsurance)-incometax;

   System.out.println("Your gross income is : £" + income) ;
   System.out.println("Your income tax is : £" + incometax) ;
   System.out.println("Your nationalinsurance  £" + nationalinsurance) ;
   System.out.println("Your pension is : £" + pension) ;
   System.out.println("Your net income is : £" + netincome) ;

}

}

Answer 1

它要求float值并等待您输入一个值。尝试添加： System.out.println("Enter a value:"); 就在此之前 income = in.nextFloat(); 使这一事实更加明显。

然后输入一个浮动值，如5，然后按“Enter”。

Answer 2

在阅读标准输入之前你没有提示任何东西，所以只需输入一个数字然后点击返回即可运行。

Answer 3

我不确定你遇到的问题是什么。当我运行它，它工作得很好。我花了一秒钟才意识到它正在等待用户输入，但是一旦我想出来，我只输入一个数字，点击输入，它就可以了。如果我是你，我会向用户添加提示，例如：

System.out.println("Please enter your income: ");
income = in.nextFloat();

Java程序挂起

3 个答案: