Question

我有这样的代码

try {
        ServerSocket serverSocket = null;
        try {
            serverSocket = new ServerSocket(888);
        } catch (IOException e) {}

        Socket clientSocket = null;
        try {
            clientSocket = serverSocket.accept();
        } catch (IOException e) {}

        out = new PrintWriter(clientSocket.getOutputStream(), true);
        in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
        String inputLine, outputLine;

        while ((inputLine = in.readLine()) != null) {
            outputLine = "SRV:>"+inputLine+"<:VRS";
            out.println(outputLine);
            taWyjscie.append(outputLine+"\n");
            if (inputLine.equals("Bye."))
                break;
        }

        out.close();
        in.close();
        clientSocket.close();
        serverSocket.close(); 

    } catch (IOException ex) {
        taWyjscie.append("Błąd I/O: "+ex.getLocalizedMessage() + "\n");
    }

它可以工作，但是在客户端发送“再见”之前，应用程序无法使用。

我希望能够通过gui从服务器向客户端发送消息，所以我与SwingWorker打架，我得到了这个：

try {
        ServerSocket serverSocket = null;
        try {
            serverSocket = new ServerSocket(888);
        } catch (IOException e) {}

        Socket clientSocket = null;
        try {
            clientSocket = serverSocket.accept();
        } catch (IOException e) {}

        out = new PrintWriter(clientSocket.getOutputStream(), true);
        in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
        String inputLine, outputLine;

        zadanie = new ServerTask(in);

    } catch (IOException ex) {
        taWyjscie.append("Błąd I/O: "+ex.getLocalizedMessage() + "\n");
    }

 private class ServerTask extends SwingWorker<String, String> {
    private BufferedReader iin;

    public ServerTask(BufferedReader win) {
        this.iin = win;
    }


    @Override
    protected String doInBackground() throws Exception {
        String input;
        while ((input = iin.readLine()) != null) {
            System.out.println(input);
            publish(input);
            if (isCancelled())
                break;
        }
        return null;
    }
    @Override
    protected void process(List<String> chunks) {
        for(String el : chunks) {
            textAreaOUT.append(el+"\n");
        }
    }

}

现在我无法从服务器向客户端发送消息，但是来自客户端的消息不会显示在textArea中。我从早上起就打架了，我不知道swingworker是如何工作的......

PS。这个尝试...前面的catch是按钮动作执行功能（如果它有任何差异）

Answer 1

您永远不会在execute上致电SwingWorker，这是您的第一个错误。从那里开始......

SwingWorker并从套接字中检索数据

1 个答案: