Question

如何在对象中调用方法，该方法的泛型参数类型为SortedMap<Integer,Vector<double[]>>？

// "c" is actually a class of mine that extends Thread
Class<?> cls = Class.forName(c.getClass().getName());

Method meth = cls.getMethod("add", new Class[]{??????});  // What do I put here?

meth.invoke(c, allData);

不确定要放入new Class[]{}数组中的内容。我试过了SortedMap.class，但这不起作用

Answer 1

Class.getMethod()这些天使用varags。你试过吗

 Method meth = cls.getMethod("add", Map.class);

Answer 2

以下代码适用于我：


public class MyClass {

public void test(ArrayList<String> p) {
    System.out.append("INVOKED !!");
}

public static void main(String[] args) throws NoSuchMethodException, ClassNotFoundException, IllegalAccessException, IllegalArgumentException, InvocationTargetException {
    MyClass myClass = new MyClass();
    Class<?> klass = Class.forName("MyClass");

    Method m = klass.getMethod("test", ArrayList.class);
    m.invoke(myClass, new ArrayList<String>());
}


}

如何调用泛型参数类型的方法，如SortedMap <integer，vector <double []>＆gt; </integer，vector <double []>

2 个答案: