Question

我正在使用xml解析器从文件夹中读取HTML文件，该解析器将清洁代码存储在tagNode

中

try {
    Document doc = new DomSerializer(props, true).createDOM(tagNode);
} catch (Exception ex) {
 ex.printStackTrace();
}

但其中一个文件给我一个错误：

org.w3c.dom.DOMException: INVALID_CHARACTER_ERR: An invalid or illegal XML character is specified.

如何在发现异常后继续运行程序？

解决方案＃1

    try 
    {
            File folder = new File(path);
            File[] listOfFiles = folder.listFiles();
        FileWriter fstream = new FileWriter("dataset.txt");
            BufferedWriter br= new BufferedWriter(fstream);


for (int i = 0; i < listOfFiles.length; i++) {    
{
        try {
            Document doc = new DomSerializer(props, true).createDOM(tagNode);
        } catch (Exception ex) {
         ex.printStackTrace();
        }
    }
    } catch (Exception ex) {
         ex.printStackTrace();
        }

考虑到解决方法，为什么我会收到此错误？

Answer 1

使用try / catch块

try{
   Document doc = new DomSerializer(props, true).createDOM(tagNode);
}
catch(DOMException e){
   //error handling here if you want
}

 //we now hit more code

Answer 2

如果您正在处理上面提到的文件列表，则只需要for循环内的try-catch块：

File folder = new File(path);
File[] listOfFiles = folder.listFiles();
FileWriter fstream = new FileWriter("dataset.txt");
BufferedWriter br= new BufferedWriter(fstream);

for (int i = 0; i < listOfFiles.length; i++)  
{
    try 
    {
       Document doc = new DomSerializer(props, true).createDOM(tagNode);
    } 
      catch (DOMException de) 
      {
         de.printStackTrace();
      }
}

如何在Java中抛出异常后继续执行？

2 个答案: