Question

我创建一个按钮并将标题设置为“单击此处”。当我按下该按钮时，我想获得该按钮标题并记录下来。这是我的代码，我哪里错了？

-(void)clicketbutton {
    UIButton *mybutton = [UIButton buttonWithType:UIButtonTypeCustom];
    [mybutton setTitle:@"Click here"  forState:UIControlStateNormal];
    [mybutton addTarget:self  
       action:@selector(displayvalue:)forControlEvents:UIControlEventTouchUpInside]; 
}

-(void)displayvalue:(id)sender {       
    UIButton *resultebutton= [UIButton buttonWithType:UIButtonTypeCustom];

    resultebutton=sender;// pls clear here.. my question here , it it possible or not. if possible how ?
    NSLog(@" The buttontitile is %@ ", [resultebutton.Title] // here also.
}

Answer 1

您的displayvalue：方法应如下所示：

-(void)displayvalue:(id)sender {       
    UIButton *resultButton = (UIButton *)sender;
    NSLog(@" The button's title is %@.",  resultButton.currentTitle);
}

（请查看XCode中的文档，它会给你正确的答案。）

Answer 2

-(void)displayvalue:(id)sender 
{
    UIButton *resultebutton= (UIButton*)sender;
    NSLog(@"The button title is %@ ", resultebutton.titleLabel.text);
}

Answer 3

我知道这是一个古老的问题，但这可能是解决这个问题的最佳方法。

NSLog(@"The button title is: %@", [sender currentTitle]);

修改
我刚刚意识到这取决于您已将接收参数设置为UIButton*的事实。而不是使用默认id，创建UIButton对象并将(id)sender投射到该按钮。剪掉中间人并将函数签名设置为

-(void)buttonPressed:(UIButton*)sender{ NSLog(@"Button title: %@",sender.currentTitle); }

这有效地转换了函数参数

Answer 4

-(void)clicketbutton {
    UIButton *mybutton = [UIButton buttonWithType:UIButtonTypeCustom];
    [mybutton setTitle:@"Click here"  forState:UIControlStateNormal];
    [mybutton addTarget:self  
       action:@selector(displayvalue:)forControlEvents:UIControlEventTouchUpInside]; 
}
-(void)displayvalue:(id)sender {       

     NSLog(@"The title is %@ ", [mybutton titleForState:UIControlStateNormal]);

}

在事件处理程序中获取UIButton的标题

4 个答案: